to find the x-intercept of a function, we simply set y = 0 and then solve for "x", so, let's first find the equation of it and then set y = 0.
![\bf (\stackrel{x_1}{-12}~,~\stackrel{y_1}{16})~\hspace{10em} slope = m\implies-\cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-16=-\cfrac{2}{3}[x-(-12)] \\\\\\ y-16=-\cfrac{2}{3}(x+12)\implies \stackrel{\stackrel{y}{\downarrow }}{0}-16=-\cfrac{2}{3}x-8\implies -8=-\cfrac{2x}{3} \\\\\\ -24=-2x\implies \cfrac{-24}{-2}=x\implies 12=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (12,0) ~\hfill](https://tex.z-dn.net/?f=%5Cbf%20%28%5Cstackrel%7Bx_1%7D%7B-12%7D~%2C~%5Cstackrel%7By_1%7D%7B16%7D%29~%5Chspace%7B10em%7D%20slope%20%3D%20m%5Cimplies-%5Ccfrac%7B2%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20%5Cbegin%7Barray%7D%7B%7Cc%7Cll%7D%20%5Ccline%7B1-1%7D%20%5Ctextit%7Bpoint-slope%20form%7D%5C%5C%20%5Ccline%7B1-1%7D%20%5C%5C%20y-y_1%3Dm%28x-x_1%29%20%5C%5C%5C%5C%20%5Ccline%7B1-1%7D%20%5Cend%7Barray%7D%5Cimplies%20y-16%3D-%5Ccfrac%7B2%7D%7B3%7D%5Bx-%28-12%29%5D%20%5C%5C%5C%5C%5C%5C%20y-16%3D-%5Ccfrac%7B2%7D%7B3%7D%28x%2B12%29%5Cimplies%20%5Cstackrel%7B%5Cstackrel%7By%7D%7B%5Cdownarrow%20%7D%7D%7B0%7D-16%3D-%5Ccfrac%7B2%7D%7B3%7Dx-8%5Cimplies%20-8%3D-%5Ccfrac%7B2x%7D%7B3%7D%20%5C%5C%5C%5C%5C%5C%20-24%3D-2x%5Cimplies%20%5Ccfrac%7B-24%7D%7B-2%7D%3Dx%5Cimplies%2012%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20~%5Chfill%20%2812%2C0%29%20~%5Chfill)
Answer:
n = 9/4 = 2.250
Step-by-step explanation:
Rearrange: 4*n-(9)=0
Solve: 4n-9 = 0
4n = 9
n = 9/4 = 2.250
answer: n = 9/4 = 2.250
The sine of any acute angle is equal to the cosine of its complement. the cosine of any angle is equal to the sine of its complement also
How many cartons of nails it takes to shingle a roof duh
Answer:
- <u>First blank: the equation of the line that passes through A and B</u>
<u></u>
- <u>Second blank: is a solution of the equation</u>
Explanation:
Three or more points are collinear if and only if they are on the same line, and, thus they are solutions, of the same equation of the line.
When you know two points through their coordinates you can always find the equation of the line:
You can find the slope, m, of that line by using the slope formula:
- m = rise / run = Δy / Δx = (y₂ - y₁) / (x₂ - x₁)
And then, you apply the point-slope equation:
Since you know m, x₁, and y₁, your equation is determined.
Once you have your equation, substitute the x and y coordinates with the coordinates of the point C. If, and only if, the equation is satisfied, the point C is on the same line and the three points are collinear.
