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Roman55 [17]
3 years ago
13

I have another question for u guys could u plz help me out? so here it is? Anthony threw a ball from the top of a 10-story build

ing that was 165 feet tall. The equation g(165-h)=1/2v^2 can be used to find the maximum height the ball can attain after being thrown from the top of the building. In this equation g represents the acceleration due to gravity (32 feet per second squared), h is the maximum height attained by the ball, and v is the speed of the ball.
rewrite the equation to highlight the maximum height attained by the ball, h.
Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0
For this case we have the following equation:
 g (165-h) = 1 / 2v ^ 2
 We must clear the value of h.
 Step 1:
 Pass g to divide:
 (165-h) = (1/2) ((v ^ 2) / g)
 Step 2:
 Pass 165 subtracting:
 -h = (1/2) ((v ^ 2) / g) -165
 Step 3:
 Multiply both sides of the equation by -1:
 h = - (1/2) ((v ^ 2) / g) +165
 Answer:
 The equation to highlight the maximum height attained by the ball, h is:
 h = - (1/2) ((v ^ 2) / g) +165
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Can you help me figure out if my this answer is correct...<br> 3(4x+ 5y +6)= 12×+15y+18
svetlana [45]

Answer: Yes, well done.

Step-by-step explanation:

3(4x+5y+6)=12x+15y+18\\(3*4x)+(3*5y)+(3*6)=12x+15y+18\\12x+15y+18=12x+15y+18

6 0
3 years ago
Select the two values of x that are roots of this equation.<br> 2x^2+ 1 = 5x
iren [92.7K]

Answer:

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

Step-by-step explanation:

One is asked to find the root of the following equation:

2x^2+1=5x

Manipulate the equation such that it conforms to the standard form of a quadratic equation. The standard quadratic equation in the general format is as follows:

ax^2+bx+c=0

Change the given equation using inverse operations,

2x^2+1=5x

2x^2-5x+1=0

The quadratic formula is a method that can be used to find the roots of a quadratic equation. Graphically speaking, the roots of a quadratic equation are where the graph of the quadratic equation intersects the x-axis. The quadratic formula uses the coefficients of the terms in the quadratic equation to find the values at which the graph of the equation intersects the x-axis. The quadratic formula, in the general format, is as follows:

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

Please note that the terms used in the general equation of the quadratic formula correspond to the coefficients of the terms in the general format of the quadratic equation. Substitute the coefficients of the terms in the given problem into the quadratic formula,

\frac{-b(+-)\sqrt{b^2-4ac}}{2a}

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

Simplify,

\frac{-(-5)(+-)\sqrt{(-5)^2-4(2)(1)}}{2(2)}

\frac{5(+-)\sqrt{25-8}}{4}

\frac{5(+-)\sqrt{17}}{4}

Rewrite,

\frac{5(+-)\sqrt{17}}{4}

\frac{5+\sqrt{17}}{4},      \frac{5-\sqrt{17}}{4}

8 0
3 years ago
A school bus has 25 seats, with 5 rows of 5 seats. 15 students from the first grade and 5 students from the second grade travel
kow [346]

Answer:

5P5×20P15

Step-by-step explanation:

A school bus has 25 seats, with 5 rows of 5 seats.

15 students from the first grade and 5 students from the second grade travel in the bus.

second-grade students occupy the first row.

The 5 students of second grade are to be seated in 5 seats,this can be done in:

5P5 ways where P is the permutation

Now 15 students from first grade are to be arranged in remaining 20 seats

This can be done in:

20P15 ways

Hence, total ways student can be seated is:

5P5×20P15

6 0
3 years ago
Does anyone know how to do this?
kolezko [41]

Answer:

  • x = 1
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Step-by-step explanation:

The coefficients of x and y do not have any "nice" relations, so doing this by elimination is just "brute force" with no particular subtlety.

After multiplying by appropriate numbers, you want the coefficient of one of the variables in one equation to be the opposite of the coefficient of the same variable in the other equation. Here, we can get that by multiplying the first equation by 7 and the second equation by 2.

  7(2x +3y = -19)   ⇒   14x +21y = -133

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Adding these equations with opposite x-coefficients eliminates the x-terms. (That is how the "elimination" method gets its name.)

  (14x +21y) +(-14x +4y) = (-133) +(-42)

  25y = -175 . . . . . . . . simplify

  y = -7 . . . . . . . . . . . divide by 25

Substituting this value into the first equation gives ...

  2x +3(-7) = -19

  2x = 2 . . . . . . . . . add 21

  x = 1 . . . . . . . . . divide by 2

The solution is x = 1, y = -7.

_____

<em>Additional comment</em>

The multipliers used in this process are essentially the coefficients of one of the variables, with one of them negated. Here, we chose the x-coefficients, because negating one of them gives two positive multipliers. We judge it easier to do the arithmetic using positive numbers.

Had we chosen to use the y-coefficients (3 and 2) for our multipliers, we would probably multiply the first equation by 2, and the second equation by -3. That way, the remaining x-coefficient would be positive.

Planning ahead is helpful, but not essential. It can help to avoid errors and make the work easier to do.

3 0
2 years ago
The temperature at noon was -17 degrees at 6 pm the temperature was -14 degrees. What was the change in temperature degrees?
irina [24]

Answer: the change in tempature was -3 degrees

Step-by-step explanation: hope this helps

5 0
2 years ago
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