Question

Simplify the expression below.                                                                                           . 2x^3 - 12x^2 + 18x - 108 / x - 6A) 4x^2 + 9xB) 2x^2 + 18
c. 3x + 5D) 3x + 2

Answer 1

$\dfrac{2x^3-12x^2+18x-108}{x-6}=\dfrac{2x^2(x-6)+18(x-6)}{x-6}\\\\=\dfrac{(x-6)(2x^2+18)}{x-6}=2x^2+18\\\\Answer:\ B)\ 2x^2+18$