These dot plots show the ages in years for sample of sea turtles and sample of koi fish

Mathematics

1 answer:

sineoko [7]3 years ago

7 0

Answer:

B. Centers: the sea turtles have a greater median age than the koi

D. Spreads: the ages of the koi are more spread out

Step-by-step explanation:

The difference between the center and spread of the data distribution of koi and sea turtles as shown in the dot plots are as follows:

==>Median:

For Koi, the median value is the 14th value represented by the 14th dot on the plot, which is 30.

The median value for koi is between the 7th and the 8th value represented by dots on the plot. The average of both values will give us 55 as the median value for koi.

Therefore, the median age of sea turtle is greater than that of koi.

==>Spread:

Koi has a range of 45 (60-15), while sea turtles have a range of 20 (65-45). Invariably, mere looking at the dot plot, we can conclude that ages of the koi are more spread out.

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dalvyx [7]

The midpoint is at (3/10 , 3/2 , 4/10)

In the given statement is

To find the midpoint of the line segment joining the pair of points

F (3/5, 0, 4/5) and G(0,3,0)

Midpoint:

The coordinates of the midpoint of a line segment are the average of the coordinates of the end points.

m = (A +B)/2

If we are given three points and we wish to find the midpoint of those points, we need to use the midpoint formula m =( $\frac{x_{1}+x_{2} }{2}$ , $\frac{y_{1}+y_{2} }{2} , \frac{z_{1}+z_{2} }{2}$ )