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tangare [24]
3 years ago
5

Sunshine the cow eats 3/5 of a bale of hay a day.How many bales of hay will she eat in a week?

Mathematics
2 answers:
Lorico [155]3 years ago
7 0
7 day in a week so 3/5×7= 4.2

or 4 1/5 bales of hay
inessss [21]3 years ago
6 0
3/5 x 7 = 21/5 bales of hay in a week.

Also represented by 3/5 + 3/5 + 3/5 + 3/5 + 3/5 + 3/5 +3/5

= 3+3+3+3+3+3+3
_______________
              5

= 21/5

There is 7 days in a week, and 3/5 bales per day
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Lane went to the bookstore he spent 1/3 of his money on a pen and 4/6 of it on books what fraction of his money did he have left
Mumz [18]

Answer: I believe that it might be $1.00


Step-by-step explanation: Well the problem doesn’t tell you how much money he HAD, so if you do 1/3+4/6 you should get 6/6 or 1 as the amount that Lane had.


3 0
3 years ago
Read 2 more answers
If a 3 foot pole casts a 4 foot shadow, how high a pole casts a 72 foot shadow?
forsale [732]
73 foot showed.......................
8 0
3 years ago
Solve for t:<br> t + 7 = 21<br><br> A: t= 28<br> B: t= 14<br> C: t= -28<br> D: t= -14
tatiyna

t + 7 = 21

---Subtract 7 from both sides

t + 7 - 7 = 21 - 7

t = 14

Hope this helps!! :)

4 0
3 years ago
Read 2 more answers
The reciprocal of 5 plus the reciprocal of 7 is the reciprocal of what number?
Natalija [7]
2/5 is the answer so the reciprocal would be 5/2
4 0
3 years ago
Read 2 more answers
High School Pre Cal
krok68 [10]
We know that
1) Sandra can run a mile in 6 minutes-------> 6*60-----> 360 sec
2) 4 laps around the track equals 1 mile
so
4 laps around the track in 360 sec
1 lap in 360/4--------> 90 sec
3) the position of Sandra for t=90 sec must be equal to the point S (0,56)
I proceed to analyze each case for t=90 sec

case a) x(t)=-140 cos(pi*t/45)    y(t)=112 sin(pi*t/45)
x(t)=-140 cos(pi*90/45)------> -140
y(t)=112 sin(pi*90/45)-------> 0
the position is the point (-140,0)------> is not the point S

case b) x(t)=140 sin(pi*t/90)  y(t)=-112 cos(pi*t/90)

x(t)=140 sin(pi*90/90)------> 0
y(t)=-112 cos(pi*90/90)-------> 112
the position is the point (0,112)------> is not the point S
<span>
case c) x(t)=-70 sin(pi*t/45)  y(t)=56 cos(pi*t/45)
</span>x(t)=-70 sin(pi*90/45)------> 0
y(t)=56 cos(pi*90/45) -------> 56
the position is the point (0,56)------> is equal to the point S----> is the solution

case d) x(t)=70 cos(pi*t/90)  y(t)=-56 sin(pi*t/90)

x(t)=70 cos(pi*90/90)------> -70
y(t)=-56 sin(pi*90/90)-------> 0
the position is the point (-70,0)------> is not the point S

 therefore

the answer is the option C

x(t)=-70 sin(pi*t/45)  y(t)=56 cos(pi*t/45)


7 0
3 years ago
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