3x+y=8 I really don't understand this and I have tried to get the answer but always end up wrong.
1 answer:
Answer:
The solution of the system of the equation is (2, 2)
Step-by-step explanation:
Let us solve the system of equations
∵ 3x + y = 8 ⇒ (1)
∵ 3x - y = 4 ⇒ (2)
→ Add equations (1) and (2) to eliminate y
∴ (3x + 3x) + (y + -y) = (8 + 4)
∴ 6x + 0 = 12
∴ 6x = 12
→ Divide both sides by 6 to find x
∵
∴ x = 2
→ Substitute the value of x in equation (1) to find y
∵ 3(2) + y = 8
∴ 6 + y = 8
→ Subtract 6 from both sides
∵ 6 - 6 + y = 8 - 6
∴ y = 2
∴ The solution of the system of the equation is (2, 2)
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Answer:
The remainder is -2.
Step-by-step explanation:
According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (<em>x</em> - <em>a</em>), then the remainder of the operation will be given by P(a).
Our polynomial is:
And we want to find the remainder when it's divided by the binomial:
We can rewrite our divisor as (<em>x</em> - (-1)). Hence, <em>a</em> = -1.
Then by the PRT, the remainder will be:
The remainder is -2.