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Blababa [14]
2 years ago
11

What is the lateral area of a pyramid with base edges 5 ft and surface area 55 ft2?

Mathematics
2 answers:
finlep [7]2 years ago
5 0
The answer is  30 ft²

The surface area (SA) of a pyramid is the sum of lateral area (LA) of the pyramid and the area of its base (BA):
SA = LA + BA

The area of the pyramid base (which is a square) with base edge a is:
BA = a²

We have:
SA = 55 ft²
LA = ?
a = 5 ft

LA = SA - BA = SA - a²
LA = 55 - 5²
LA = 55 - 25
LA = 30 ft²

HOPE THIS HELPS;)
stich3 [128]2 years ago
3 0
Lateral Area = Surface Area - Area of Base. 
<span> that'll be 55ft^2 - 25ft^2 = 30ft^2.</span>
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<h3>What are Trigonometric functions?</h3>

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\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\

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1st.) x = 5 /Sin(30°)

x = 10

!) sin(45°) = 4/x

x = 4/sin(45°)

x = 4√2

I) Cos(45°) = √3 / x

x = √3 / Cos(45°)

x = √6

E) Tan(60°) = 3√3 / x

x = 3√3 / 3

W) For isosceles right-triangle, the angle made by the legs and the hypotenuse is always 45°.

x = 45°

N) x² + x² = (7√2)²

x = 7

V) Tan(60°) = 7 / x

x = 7√3/3

K) x² + x² = (9)²

x = 9/√2

Y) Sin(60°) = 7√3/x

x = 14

M) Sin(30°) = x/11

x = 11/2

T) Sin(45°) = x/√10

x = √5

A) x + 2x + 90° = 180°

x = 30°

O) Sin(45°) = √2 / x

x = 2

R) Tan(30°) = x / 4

x = 4/√3 = 4√3 / 3

S) Sin(60°) = x / (10/3)

x = 5√3 / 3

Learn more about Trigonometric functions:

brainly.com/question/6904750

#SPJ1

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1 year ago
The figure below shows an upside-down pyramid with a square base.
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Answer:

B

Step-by-step explanation:

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