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FromTheMoon [43]
2 years ago
11

Does anyone know this?

Mathematics
1 answer:
aniked [119]2 years ago
7 0

Answer:

h(1)= 1

h(4)=5

Step-by-step explanation:

Given

h(x)= x^3 for 1≤x≤3

and

h(x)=5 x>3

Now finding h(1), i.e when x=1

x=1 lies in the range 1≤x≤3 hence putting value x=1 in x^3

h(1)= 1^3

     = 1

Now finding h(4), i.e when x=4

x=1 lies in the range x<3 hence putting value x=4 in h(x)=5

h(4)= 5 !

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motikmotik

Hey there!

Line passes through (4, -1) & is parallel to 2x -3y=9

Let's start off by identifying what our slope is. In the slope-intercept form y=mx+b, we know that "m" is our slope.

The given equation needs to be converted into slope-intercept form and we can do this by getting y onto its own side of the equal sign.

Start off by subtracting 2x from both sides.

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"M" is simply a place mat so if we look at our given line, the "m" value is 2/3. Therefore, our slope is 2/3.

We should also note that we're looking for a line that's parallel to the given one. This means that our new line has the same slope as our given line. Therefore, our new line has a slope of 2/3.

Now, we use point-slope form ( y-y₁=m(x-x₁) ) to complete our task of finding a line that passes through (4, -1). Our new slope is 2/3 & it passes through (4, -1).

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Simplify.

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Simplify by subtracting 1 from both sides.

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y = 2/3x + 5/3

~Hope I helped!~

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