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FromTheMoon [43]
3 years ago
11

Does anyone know this?

Mathematics
1 answer:
aniked [119]3 years ago
7 0

Answer:

h(1)= 1

h(4)=5

Step-by-step explanation:

Given

h(x)= x^3 for 1≤x≤3

and

h(x)=5 x>3

Now finding h(1), i.e when x=1

x=1 lies in the range 1≤x≤3 hence putting value x=1 in x^3

h(1)= 1^3

     = 1

Now finding h(4), i.e when x=4

x=1 lies in the range x<3 hence putting value x=4 in h(x)=5

h(4)= 5 !

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Sergio039 [100]

Answer:

C) (1,3) and ( 4,0)

The intersecting points of two given curves are A( 1,3) and B(4,0)

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given Parabola  y = x² – 6x + 8  and straight line y = -x +4

      y = x² – 6x + 8   ...(i)

      y = -x +4  ...(ii)

Equating (i) and (ii) equations , we get

  x² – 6x + 8  = -x +4

⇒ x² – 6x + 8  +x - 4 = 0

⇒ x² – 5x +  4 = 0

⇒ x² – 4x -x + 4 = 0

⇒ x ( x-4) -1( x -4) =0

⇒ (x -1) ( x -4) =0

⇒ x =1 and x = 4

<u><em>Step(ii):-</em></u>

Put x = 1 in equation y = -x +4

  y = -1 +4 = 3

The first point A( 1,3)

Put x = 4 in equation y = -x +4

y = -4+4 =0

The second point B(4,0)

<u><em>Final answer:</em></u>-

The intersecting points of two given curves are A( 1,3) and B(4,0)

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There are 17 hops in a hop, a skip, and a jump.

<h3></h3><h3>How to perform changes of units?</h3>

We have the relations:

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So we have:

1 hop + 1 skip + 1 jump.

First, using the second relation we rewrite:

1 hop + 1 skip + 3 skips = 1 hop + 4 skips.

Now, using the first relation:

1 hop + 4 skips = 1 hop + 4*(4 hops) = 1 hop + 16 hops = 17 hops.

There are 17 hops in a hop, a skip, and a jump.

If you want to learn more about changes of units:

brainly.com/question/9032119

#SPJ1

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If you roll a six sided die what is the probably that the sum is 5 or lower?
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Step-by-step explanation:

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  y = 8 . . . . multiply by 4

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