Answer:
(a) There are outliers
(b) 
and 
Step-by-step explanation:
Given
Solving (a): Check for outliers
This is calculated using:
--- lower bound of outlier
--- upper bound of outlier
Where
So, we have:
The lower bound of outlier becomes
The upper bound of outlier becomes
So, we have:
--- the range without outlier
Given that:
--- This represents the lowest data
--- This represents the highest data
-24 and 64 are out of range of .
Hence, there are outliers
Solving (b): The outliers
The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)
So, the outliers are:
and
If the length of a rectangle is a two-digit number with identical digits and the width is 1/10 the length and the perimeter is 2 times the area of the rectangle, what is the the length and the width
Solution:
Let the length of rectangle=x
Width of rectangle=x/10
Perimeter is 2(Length+Width)
= 2(x+x/10)
Area of Rectangle= Length* Width=x*x/10
As, Perimeter=2(Area)
So,2(x+x/10)=2(x*x/10)
Multiplying the equation with 10, we get,
2(10x+x)=2x²
Adding Like terms, 10x+x=11x
2(11x)=2x^2
22x=2x²
2x²-22x=0
2x(x-11)=0
By Zero Product property, either x=0
or, x-11=0
or, x=11
So, Width=x/10=11/10=1.1
Checking:
So, Perimeter=2(Length +Width)=2(11+1.1)=2*(12.1)=24.2
Area=Length*Width=11*1.1=12.1
Hence, Perimeter= 2 Area
As,24.2=2*12.1=24.2
So, Perimeter=2 Area
So, Answer:Length of Rectangle=11 units
Width of Rectangle=1.1 units
Answer:
The given points are
The setting would have a interval or 2 units above and below the minimum and maximum of each coordinate.
The given maxium horizontal coordinate is 0.
The given minimum horizontal coordinate is -13.
The given maximum vertical coordinate is 3.
The given minimum vertical coordinate is -7.
Now, we extend each maximum and minimum value by 2 units to create the setting.
So, the setting is
With a scale of 2 units.
Are there aby answer choices?
