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dangina [55]
2 years ago
7

A six-sided dice is rolled twice. Find the probability that the larger of the two rolls was equal to 5.

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
8 0

The probability that the larger of the two rolls was equal to 5 is; 2/9

<h3>Probability of possible outcomes</h3>

The total number of possible outcomes when the dice is rolled twice is 36 outcomes.

Now, for the larger of the two rolls to equal 5, the total number of favourable  outcomes are 8 which are;

(1, 5), (2, 5), (3, 5), (4, 5), (5, 1), (5, 2), (5, 3), (5,4)

Thus, probability that the larger of the two rolls was equal to 5 is;

P(larger of 2 rolls equals 5) = 8/36 = 2/9

Read more about probability of possible outcomes at; brainly.com/question/19916581

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Answer:

D

Step-by-step explanation:

Plug in and see.

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The temperature in Waterloo was − 5°C at sunrise. By noon the temperature had risen by 12 Celsius degrees. What was the temperat
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We can write a mixed number as an improper fraction by multiplying the denominator by the whole number and adding the numerator.

We can change 4\frac{2}{7} to the improper fraction 30/7.

We can also change 2\frac{1}{5} to the improper fraction 11/5.

Now, we are simply multiplying fractions. To multiply fractions, we multiply across the numerators and multiply across the denominators. When we multiply these fractions, we will end up with the fraction 330/35. Since 330/35 is not in lowest terms, we need to divide both the numerator and denominator by the greatest common factor of 330 and 35 which is 5 and we will get the improper fraction 66/7.

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66 divided by 7 equals 9 with a remainder of 3 so we can write 66/7 as the mixed number 9 and 3/7.

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