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dangina [55]
2 years ago
7

A six-sided dice is rolled twice. Find the probability that the larger of the two rolls was equal to 5.

Mathematics
1 answer:
Diano4ka-milaya [45]2 years ago
8 0

The probability that the larger of the two rolls was equal to 5 is; 2/9

<h3>Probability of possible outcomes</h3>

The total number of possible outcomes when the dice is rolled twice is 36 outcomes.

Now, for the larger of the two rolls to equal 5, the total number of favourable  outcomes are 8 which are;

(1, 5), (2, 5), (3, 5), (4, 5), (5, 1), (5, 2), (5, 3), (5,4)

Thus, probability that the larger of the two rolls was equal to 5 is;

P(larger of 2 rolls equals 5) = 8/36 = 2/9

Read more about probability of possible outcomes at; brainly.com/question/19916581

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The length of time a full length movie runs from opening to credits is normally distributed with a mean of 1.9 hours and standar
Margarita [4]

Answer:

  1. 0.26
  2. 0.91
  3. 1.43

Step-by-step explanation:

given data

mean = 1.9 hours

standard deviation = 0.3 hours

solution

we get here first  random movie between 1.8 and 2.0 hours

so here

P(1.8 < z < 2 )

z = (1.8 - 1.9) ÷ 0.3

z = -0.33

and

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P(-0.333 < z < 0.333 )

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and

A movie is longer than 2.3 hours.

P(x > 2.3)

P( \frac{x-\mu }{\sigma}  > \frac{2.3-\mu }{\sigma} )

P (z  > \frac{2.3-1.9 }{0.3}  )

P (z  > 1.333  )

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so chance a movie is longer than 2.3 hours is 0.091

and

length of movie that is shorter than 94% of the movies is

P(x > a ) = 0.94

P(x <  a ) = 0.06

so

P( \frac{x-\mu }{\sigma } <  \frac{a-\mu }{\sigma } )

\frac{a-1.9 }{0.3 } = -1.55

a = 1.43

so length of the movie that is shorter than 94% of the movies about 1.4 hours.

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