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4 years ago

Consider the expressions 4t+t and 1t+4t .

1 answer:

5 0

So the full equation would be

4(3)+3 and 1(3)+4(3)

12+3 and 3+12

15 and 15

So your answer is 15 for both problems

Hope this helped. Have a great day!

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What is the equation of the following line? Be sure to scroll down first to see all answer options.

Serjik [45]

Answer:

<h3>The answer is option F</h3>

Step-by-step explanation:

Equation of a line is y = mx + c

where

m is the slope

c is the y intercept

To calculate the equation of the line first find the slope

Slope of the line using points

(0 , 0) and (4 , -2) is

$m = \frac{ - 2 - 0}{4 - 0} = \frac{ - 2}{4} = - \frac{1}{2}$

Now use the formula

y - y1 = m(x - x1) to find the equation of the line using any of the points

Using point (0,0)

That's

$y - 0 = - \frac{ 1}{2} (x - 0)$

The final answer is

$y = - \frac{1}{2} x$

Hope this helps you

4 0

3 years ago

Read 2 more answers

Where would you start dividing to find the quotient of 3,825/8 explain how you know

Vadim26 [7]

You divide left to right so you start at the three, hope this helps.

8 0

3 years ago

Read 2 more answers

Explain why 6 times a number can be decomposed into 2 equal addends

Gnoma [55]

Because 6 is a even number and you can divide is by any thing

4 0

4 years ago

The side length, s, of a cube is 4x2 3. if v = s3, what is the volume of the cube? 64x6 144x4 108x2 27 64x6 48x4 12x2 1 4x6 36x4

sdas [7]

The volume of the cube given the dimensions of the side length is $64x^{6} + 144x^{4} + 108x^{2} + 27$

<h3>What is the volume of the cube?</h3>

A cube is a 3-dimensional object that has six faces, twelve edges and eight vertices.

Volume of a cube = a³

Where a = length of a side

(4x² + 3) × (4x² + 3) = 16x^4 + 24x² + 9

(16x^4 + 24x² + 9) × (4x² + 3) = $64x^{6} + 144x^{4} + 108x^{2} + 27$

To learn more about the volume of a cube, please check: brainly.com/question/26406747

#SPJ5

3 0

2 years ago

Find the perimeter of ABC with vertices A (1,1), B (7,1), and C (1,9)

Effectus [21]

Answer:

24 unit

Step-by-step explanation:

Given,

The vertices of the triangle ABC are,

A (1,1), B (7,1), and C (1,9),

By the distance formula,

$AB=\sqrt{(7-1)^2+(1-1)^2}=\sqrt{6^2}=6\text{ unit}$

$BC=\sqrt{(1-7)^2+(9-1)^2}=\sqrt{6^2+8^2}=\sqrt{36+64}=\sqrt{100}=10\text{ unit}$

$CA=\sqrt{(1-1)^2+(1-9)^2}=\sqrt{8^2}=8\text{ unit}$

Thus, the perimeter of the triangle ABC = AB + BC + CA = 6 + 10 + 8 = 24 unit

4 0

3 years ago