im pretty sure it is 4.18x10^13
Answer:
option A
Step-by-step explanation:
the statement tell us that she slides the triangle 2 units down, so the vertical axis is the one that we are going to modify
we have the points: (1,2), (3,3) and (4,1)
so to these points we subtract "2" to the variable Y
I mean:
(1,2): 2-2=0
(3,3): 3-2=1
(4,1): 1-2=-1
finally we have:
(1,0), (3,1) and (4,-1)
Answer:
C; Circle
Step-by-step explanation:
In this question, we are interested in giving a term to the locus of points which are at a certain distance from a fixed point.
The correct answer to this is a circle.
From the question, we can picture a situation which we have the point (1,2) as the center of the circle. This point serve the starting point in which all other points which are exactly 6 units away are plotted.
Thus, from this center point, we can mark off several points around the center point. By tracing the marked points from these center, we can obtain a circular path which when traced completely will give us the identity of a circle, where these points represent the line bounding the circle which is referred to the circumference of the particular circle in question.
Further more, from the definition of the radius of a circle, it is the distance from the center of a circle to the circumference. While the point (1,2) represents the center of the circle in question, the distance 6 units stand for the radius of the circle.
Answer:
Step-by-step explanation:
Method 1: Taking the log of both sides...
So take the log of both sides...
5^(2x + 1) = 25
log 5^(2x + 1) = log 25 <-- use property: log (a^x) = x log a...
(2x + 1)log 5 = log 25 <-- distribute log 5 inside the brackets...
(2x)log 5 + log 5 = log 25 <-- subtract log 5 both sides of the equation...
(2x)log 5 + log 5 - log 5 = log 25 - log 5
(2x)log 5 = log (25/5) <-- use property: log a - log b = log (a/b)
(2x)log 5 = log 5 <-- divide both sides by log 5
(2x)log 5 / log 5 = log 5 / log 5 <--- this equals 1..
2x = 1
x=1/2
Method 2
5^(2x+1)=5^2
2x+1=2
2x=1
x=1/2
