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icang [17]
4 years ago
13

A segment has endpoints at (-2,3) and (7,9), how long is the segment?

Mathematics
2 answers:
-BARSIC- [3]4 years ago
4 0
So here we just use the Pythagorean Theorem and do: 9^2 + 6^2 = 117, then we square root that, and it gives us <span>10.8166538, which is the answer! Hope this helped! Brainliest is always appreciated!</span>
DochEvi [55]4 years ago
4 0
Use pythagorean theorem to solve the problem. The distance of the two endpoints will be the hypotenuse. See image attached.
d² = Δx² + Δy²
d² = (x₂ - x₁)² + (y₂ - y₁)²
d² = (7 - (-2))² + (9 - 3)²
d² = (7 + 2)² + 6²
d² = 9² + 6²
d² = 81 + 36
d² = 117
d = √117
d = 10.81665..
to the nearest tenth
d = 10.8 units

The length of the segments is 10.8 units

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Surface area = sqrt (108) * sqrt[(π h + 108 / h^2)] 

<span>Getting the 1st derivative dS / dh then equating to 0 to get the maxima value:</span>

dS/dh = sqrt (108) ((π – 216 / h^3) * [(π h + 108/h^2)^-1/2] 

Let dS/dh = 0 so,

 π – 216 / h^3 = 0 

h^3 = 216 / π

h = 4.10 cm

Calculating for r:

r^2 = 108 / π (4.10)

r = 2.90 cm

 

Answers:

 h = 4.10 cm

<span>r = 2.90 cm</span>

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