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igor_vitrenko [27]
3 years ago
12

The height of a projectile in feet at time t is determined by the equation h=-16t^2+128t+320. At what time will the projectile b

e 560 feet high
Mathematics
2 answers:
SpyIntel [72]3 years ago
6 0

Answer:

At 3 seconds and again at 5 seconds

Step-by-step explanation:

h = -16t² + 128t + 320

560 = -16t² + 128t + 320

16t² - 128t + 240 = 0

t² - 8t + 15 = 0

t² - 5t - 3t + 15 = 0

t(t - 5) - 3(t - 5) = 0

(t - 5)(t - 3) = 0

t = 3, t = 5

maksim [4K]3 years ago
5 0

Answer:

3 seconds and 5 seconds

Step-by-step explanation:

Let the function equal 560 ft

560=-16t^2+128t+320

Subtract 560 from each side

560-560=-16t^2+128t+320-560

0 =-16t^2+128t-240

Divide each side by -16

0/-16 = (-16t^2+128t-240)/-16

0 = t^2 -8t-15

Factor

0=(t-5)(t-3)

Using the zero product property

t-5 =0    t-3=0

t=5   t=3

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Find the major axis for the ellipse <br> x² + 16y2-96y + 128 = 0
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The major axis for the ellipse, x² + 16y² - 96y + 128 = 0 is the x-axis

To answer the question, we need to write it in the standard form of the equation of an ellipse

<h3>Equation of an ellipse</h3>

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So, x² + 16y² - 96y + 128 = 0

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