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3 years ago

Answer this and i will give brainliest

Mathematics

2 answers:

seropon [69]3 years ago

8 0

Answer:

2x = y

Step-by-step explanation:

As you can see in the table, y = 2x, this is proven by the fact that if you divide any value in the y of the table by 2 you will get its corresponding x value, proving that 2x = y is the function that is used to represent this table's value.

Mariulka [41]3 years ago

4 0

Answer:

2x = y

Step-by-step explanation:

If x = 10

2x = y

2 * 10 = y

20 = y

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In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x

Alexus [3.1K]

Answer:

Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

Step-by-step explanation:

Given Differential Equation,

$y"-2y'+y=xe^x$ ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

$\implies\:y(x)=y_c(x)+y_p(x)$

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

$y_c(x)=C_1e^x+c_2xe^x$

Now for particular solution,

let $y_p(x)=Ax^3e^x$

$y'=Ax^3e^x+3Ax^2e^x$

$y"=Ax^3e^x+6Ax^2e^x+6Axe^x$

Now putting these values in (1), we get

$Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x$

$Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x$

$6Axe^x=xe^x$

$6A=1$

$A=\frac{1}{6}$

$\implies\:y_p(x)=\frac{x^3e^x}{6}$

Therefore, Solution is $y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}$

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3 years ago

9 exponent 10<br> Divide by 9 exponent 11

Natasha_Volkova [10]

Answer:

$\frac{\sqrt{110} }{11}$ or $\frac{\sqrt{10} }{\sqrt{11} }$

Step-by-step explanation:

I assume you mean $\frac{9\sqrt{10} }{9\sqrt{11} }$

there is a common factor of 9 in the numerator and denominator so we can cancel out to form $\frac{\sqrt{10} }{\sqrt{11} }$

$\frac{\sqrt{10} }{\sqrt{11} }$ is technically a correct answer, but I will go ahead to rationalize the denominator

multiply $\frac{\sqrt{10} }{\sqrt{11} }$ by some form of 1. this case, we will use $\frac{\sqrt{11} }{\sqrt{11} }$ as our 1.

$\frac{\sqrt{10} }{\sqrt{11} }$ * $\frac{\sqrt{11} }{\sqrt{11} }$ = $\frac{\sqrt{10} *\sqrt{11} }{\sqrt{11} *\sqrt{11} }$ = $\frac{\sqrt{110} }{11}$

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3 years ago