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Aleks04 [339]
2 years ago
14

Answer this and i will give brainliest

Mathematics
2 answers:
seropon [69]2 years ago
8 0

Answer:

2x = y

Step-by-step explanation:

As you can see in the table, y = 2x, this is proven by the fact that if you divide any value in the y of the table by 2 you will get its corresponding x value, proving that 2x = y is the function that is used to represent this table's value.

Mariulka [41]2 years ago
4 0

Answer:

2x = y

Step-by-step explanation:

If x = 10

2x = y

2 * 10 = y

20 = y

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Units must be consistent. If the unit for p is dollars, the unit for i is dollars and the unit for t is years, what must the uni
umka2103 [35]

Assuming you're concerned with interest rate problems, r is generally involved in something like the formula ...

... i = prt

So, r will have the units of ...

... r = i/(pt) = (dollars)/(dollars·year) = 1/year

That is, r is <em>(some fraction) per year</em>.

_____

Often, the fraction is expressed as a percentage. The fraction will be unitless (as percentages are), leaving the units of r as year⁻¹.

5 0
3 years ago
Find the standard form of the circle x2 + y2 – 6x + 10y + 24 = 0 by completing the square.
hichkok12 [17]

Answer:

(x-3)^2+ (y+5)^2=10

Step-by-step explanation:

Given the equation of the circle: x^2 + y^2 - 6x + 10y + 24 = 0

We wish to express it in a Standard form:

We begin by re-arranging:

x^2 - 6x + y^2  + 10y  = - 24

Next, divide the coefficient of x by 2, square it and add it to both sides.

Do the same for y.

x^2 - 6x +(-3)^2+ y^2  + 10y+5^2  = - 24+(-3)^2+5^2

Next, we factorize

(x-3)^2+ (y+5)^2  = - 24+9+25\\(x-3)^2+ (y+5)^2=10

This is the standard form.

6 0
3 years ago
The scale on a map is 1 in : 50 mi . The actual distance between two cities is 350 miles
son4ous [18]
On a map, they would be 7 inches apart, if that's what you're asking.
7 0
3 years ago
Which equation demonstrates the distributive property?
olga2289 [7]

Answer:

D

Step-by-step explanation:

The distributive property takes place when you distribute what is outside of the parentheses into the parentheses, separating out the equation into easier to develop parts. D does this exactly.

8 0
3 years ago
Read 2 more answers
Whats the roots of the following three problems:
klemol [59]

QUESTION 1

The given function is

f(x)=\frac{(x-3)(x-1)}{(x-1)(x+2)}

We simplify to get;

f(x)=\frac{x-3}{x+2}

This function is equal to zero when x-3=0

\Rightarrow x=3

QUESTION 2

The given function is

f(x)=\frac{5x^2-10x+5}{2x^2-5x+3}

f(x)=\frac{5(x^2-2x+1)}{2x^2-5x+3}

We factor to get;

f(x)=\frac{5(x-1)^2}{(2x-3)(x-1)}

f(x)=\frac{5(x-1)}{(2x-3)}

This function equals zero when

5(x-1)=0

x=1

QUESTION 3

The given function is

f(x)=\frac{x^3-8}{x^2-6x+8}

We factor to get,

f(x)=\frac{(x-2)(x^2+2x+4)}{(x-2)(x+4)}

f(x)=\frac{x^2+2x+4}{x+4}

The function equals zero when x^2+2x+4=0

D=b^2-4ac

D=2^2-4(1)(4)

D=-12

Hence the equation has no real roots.

The complex roots are

x=-\sqrt{3}i-1 or x=-1+\sqrt{3}i

4 0
3 years ago
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