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algol [13]
3 years ago
5

Calculate dy/dx when y = (x2 + 2)e 4x as the derivative of a product, letting u = x2 + 2 and v = e4x . Which of the following is

a step in your solution?
A. dv/dx = 4xe3x
B. du/dx = 2x + 2
C. dv/dx = 4xe4x
D. du/dx = 2x
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
5 0

Answer:

D. du/dx = 2x

Step-by-step explanation:

Given to find dy/dx where;

y=(x^{2} +2)e^4^x

Then when you let;

u=x²+2    and

v=e^{4x}

Then

In  u=x²+2  du/dx = 2x------------------------step 1

In e^4x, dv/dx = e^4x * d/dx (4x)

=e^4x *4 = 4e^4x------------------------------------step 2

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Evaluate 3x2 - 1 when x = 2.
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You are looking at the New York ball drop on New Year’s Eve at a distance of 100 m away from the base of the structure. If the b
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The question is an illustration of related rates.

The rate of change between you and the ball is 0.01 rad per second

I added an attachment to illustrate the given parameters.

The representations on the attachment are:

\mathbf{x = 100\ m}

\mathbf{\frac{dy}{dt} = 2\ ms^{-1}} ---- the rate

\mathbf{\theta = \frac{\pi}{4}}

First, we calculate the vertical distance (y) using tangent ratio

\mathbf{\tan(\theta) = \frac{y}{x}}

Substitute 100 for x

\mathbf{y = 100\tan(\theta) }

\mathbf{\tan(\theta) = \frac{y}{100}}

Differentiate both sides with respect to time (t)

\mathbf{ \sec^2(\theta) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot \frac{dy}{dt}}

Substitute values for the rates and \mathbf{\theta }

\mathbf{ \sec^2(\pi/4) \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

This gives

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\mathbf{ 2 \cdot \frac{d\theta}{dt} = \frac{1}{100} \cdot 2}

Divide both sides by 2

\mathbf{ \frac{d\theta}{dt} = \frac{1}{100} }

\mathbf{ \frac{d\theta}{dt} = 0.01 }

Hence, the rate of change between you and the ball is 0.01 rad per second

Read more about related rates at:

brainly.com/question/16981791

8 0
2 years ago
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