Question

suppose the distnace in feet that an object travels t seconds is given by the formula d=64t^2 how far would the object travel after 1.5 * 10^3 seconds

Answer 1

Answer:

The object travels 144,000,000 feet.

Step-by-step explanation:

The distance the object travel after t seconds is given by:

$d(t) = 64t^2$

How far would the object travel after 1.5 * 10^3 seconds

This is d when $t = 1.5 \times 10^3 = 1500$, so $d(1500)$

$d(1500) = 64*1500^2 = 144000000$

The object travels 144,000,000 feet.