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Otrada [13]
3 years ago
12

suppose the distnace in feet that an object travels t seconds is given by the formula d=64t^2 how far would the object travel af

ter 1.5 * 10^3 seconds
Mathematics
1 answer:
Darya [45]3 years ago
8 0

Answer:

The object travels 144,000,000 feet.

Step-by-step explanation:

The distance the object travel after t seconds is given by:

d(t) = 64t^2

How far would the object travel after 1.5 * 10^3 seconds

This is d when t = 1.5 \times 10^3 = 1500, so d(1500)

d(1500) = 64*1500^2 = 144000000

The object travels 144,000,000 feet.

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yan [13]

The numbers are 105 and 50

<em><u>Solution:</u></em>

Let "x" be the first number

Let "y' be the second number

Twice a number plus twice a second number is 310

Therefore,

twice of x + twice of y = 310

2x + 2y = 310 ---------- eqn 1

The difference between the numbers is 55

x - y = 55 -------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

From eqn 2,

x = 55 + y ------ eqn 3

<em><u>Substitute eqn 3 in eqn 1</u></em>

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4y = 310 - 110

4y = 200

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<em><u>Substitute y = 50 in eqn 3</u></em>

x = 55 + 50

<h3>x = 105</h3>

Thus the numbers are 105 and 50

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3 years ago
Pizza Perfection sold 93 pieces on Monday 67 pizzas and Tuesday 78 pizzas on Wednesday 44 piece pizzas on Thursday and 123 pizza
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What does it mean to get a 150% salary raise? Explain in words and then give an example showing a calculation. pls and thx.
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Answer:

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