Step-by-step explanation:
A = {0,1,2,3}
a): R = {(0,0),(2,2),(3,3)}
R is antisymmetric, because if the (a,b)∈R, than a=b.
R is not reflexive, because (1,1) ∉ R while 1 ∈ A.
R is transitive, because if the (a,b)∈R and (b, c) ∈ R, than a=b=c and (a,c)=(a,a)∈R.
R is not portable ordering because R is not reflexive.
b): R = {(0,0),(1,1),(2,0),(2,2),(2,3),(3,3)}
R is antisymmetric, because if the (a,b)∈R and if the (b, a) ∈ R, than a=b (since (2,0) ∈ R and (0,2) ∉ R; and (2,3) ∈ R and (3,2) ∉ R )
R is reflexive, because (a,a) ∈ R of every element a ∈ A.
R is transitive , because if the (a,b)∈R and if the ( b , c )∈R . then a = b or b = c ( since there are only two element not of the form ( a , a ) and that pair does not satisfy ( a,b ) ∈ R and ( b , a ) ∈ R ), which implies ( a , c ) = ( b , c ) ∈ R or ( a , c ) = ( a , b ) ∈ R.
R is a partial ordering, because R is reflexive, antisymmetric and transitive.
c): R = {(0,0),(1,1),(1,2),(2,2),(3,1),(3,3)}
R is reflexive, because (a,a)∈R of every element a ∈ A.
R is antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R . then a = b ( since ( 1 , 2 )∈R and ( 2 , 1 ) ∉ R; ( 3 , 1 ) ∈ R and ( 1 , 3 ) ∉ R ).
R is not transitive , because ( 3 , 1 ) ∈ R and ( 1 , 2 )∈R, while ( 3 , 2 ) ∈ R.
R is not a partial ordering. because R is not transitive .
d): R = {(0,0),(1,1),(1,2),(1,3),(2,0),(2,2),(2,3), (3,0),(3,3)}
R is the reflexive, because ( a , a )∈R of every elements∈A.
R is the antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R, then a = b ( since ( 1 . 2 )∈R and ( 2 . 1 )∉R; similarly, all other elements not of the form (a,a) ).
R is not transitive, because ( 1 , 2 )∈R and ( 2 , 0 )∈R, while ( 1 . 0 )∉R.
R is not a partial ordering, because R is not transitive,
e): R = { ( 0 , 0 ) , ( 0, 1 ) , ( 0 , 2 ) , ( 0 , 3 ) , ( 1 , 0 ) , ( 1 , 1 ) , ( 1 , 2 ) , ( 1 , 3 ) , ( 2 , 0 ) , ( 2 , 2 ) , ( 3 , 3 ) }
R is the reflexive , because ( a , a )∈R of every element a∈A .
R is not antisymmetric, because ( 1 , 0 )∈R and ( 0 , 1 )∈R while 0 is not equal to 1.
R is not transitive, because ( 2 , 0 )∈Rand ( 0 , 3 )∈R, while ( 2 , 3 )∉R .
R is not a partial ordering, because R is not the antisymmetric and not the transitive.
