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3 years ago

Ellen sells $790 wore them of clothes and earns &39.50 in commission. What is the commission rate?

Mathematics

1 answer:

torisob [31]3 years ago

7 0

The commission rate is 5%.

Step-by-step explanation:

Given,

Cost of sold clothes = $790

Commission = $39.50

Commission rate = $\frac{commission\ amount}{Cost\ of\ sold\ clothes}*100\\$

$Commission\ rate=\frac{39.50}{790}*100\\Commission\ rate=\frac{3950}{790}\\Commission\ rate=5\%$

The commission rate is 5%.

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If ABCD congruent to QRST, measure of angle A = x – 10º, and measure of angle Q = 2x – 30º, what is the measure of angle A?

belka [17]

Congruent means they are the same,

A and Q are both the first letters, which mean they would also be the same.

Set the two equations equal to each other, solve for x then solve for angle A.

x-10 = 2x-30

Add 30 to each side:

x+20 = 2x

Subtract 1x from each side:

x = 20

Now replace x with 20 in the equation for A

A = 20-10

Angle A = 10 degrees.

3 0

3 years ago

In a study comparing various methods of gold plating, 7 printed circuit edge connectors were gold-plated with control-immersion

S_A_V [24]

Answer:

99% confidence interval for the difference between the mean thicknesses produced by the two methods is [0.099 μm , 0.901 μm].

Step-by-step explanation:

We are given that in a study comparing various methods of gold plating, 7 printed circuit edge connectors were gold-plated with control-immersion tip plating. The average gold thickness was 1.5 μm, with a standard deviation of 0.25 μm.

Five connectors were masked and then plated with total immersion plating. The average gold thickness was 1.0 μm, with a standard deviation of 0.15 μm.

Firstly, the pivotal quantity for 99% confidence interval for the difference between the population mean is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n__1+_n__2-2$

where, $\bar X_1$ = average gold thickness of control-immersion tip plating = 1.5 μm

$\bar X_2$ = average gold thickness of total immersion plating = 1.0 μm

$s_1$ = sample standard deviation of control-immersion tip plating = 0.25 μm

$s_2$ = sample standard deviation of total immersion plating = 0.15 μm

$n_1$ = sample of printed circuit edge connectors plated with control-immersion tip plating = 7

$n_2$ = sample of connectors plated with total immersion plating = 5

Also, $s_p=\sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(7-1)\times 0.25^{2}+(5-1)\times 0.15^{2} }{7+5-2} }$ = 0.216

Here for constructing 99% confidence interval we have used Two-sample t test statistics as we don't know about population standard deviations.

So, 99% confidence interval for the difference between the mean population mean, ( $\mu_1-\mu_2$ ) is ;

P(-3.169 < $t_1_0$ < 3.169) = 0.99 {As the critical value of t at 10 degree of

freedom are -3.169 & 3.169 with P = 0.5%}

P(-3.169 < $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < 3.169) = 0.99

P( $-3.169 \times {s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < ${(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}$ < $3.169 \times {s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ) = 0.99

P( $(\bar X_1-\bar X_2)-3.169 \times {s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ < ( $\mu_1-\mu_2$ ) < $(\bar X_1-\bar X_2)+3.169 \times {s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ) = 0.99

99% confidence interval for ( $\mu_1-\mu_2$ ) =

[ $(\bar X_1-\bar X_2)-3.169 \times {s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ , $(\bar X_1-\bar X_2)+3.169 \times {s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ]

= [ $(1.5-1.0)-3.169 \times {0.216\sqrt{\frac{1}{7}+\frac{1}{5} } }$ , $(1.5-1.0)+3.169 \times {0.216\sqrt{\frac{1}{7}+\frac{1}{5} } }$ ]

= [0.099 μm , 0.901 μm]

Therefore, 99% confidence interval for the difference between the mean thicknesses produced by the two methods is [0.099 μm , 0.901 μm].

6 0

3 years ago

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Solve for x. (x - 3)^2 -10 = 15

Brut [27]

Answer:

Step-by-step explanation:

Let's go:

$(x - 3)^2 - 10 = 15 \\\ (x - 3)^2 = 15 + 10 \\\ (x - 3)^2 = 25 \\\ x - 3 = \sqrt{25} \\\ x - 3 = \pm 5$

Solution #1:

x - 3 = 5

x = 5 + 3

x = 8

Solution #2:

x - 3 = - 5

x = - 5 + 3

x = - 2

I hope I helped you.

3 0

2 years ago

Find the value of x. #9,10,11,&12

ValentinkaMS [17]

Answer:

Step-by-step explanation:

9). It's given in the triangle → Two angles are equal in measure

Therefore, by the definition of an isosceles triangle, opposite sides of the equal angles are equal in measure.

x = 12

10). Two sides of the given triangles are equal in length.

By the definition of an isosceles triangle, opposite angles of the equal sides of the triangle will be equal in measure.

Therefore, y = 55°

By the triangle sum theorem,

x° + y° + 55° = 180°

x° + 55° + 55° = 180°

x = 180 - 110

x = 70°

11). By the definition of an isosceles triangle, opposite sides of the equal angles will be equal in measure.

x + 3 = 12

x = 9

12). By the definition of an isosceles triangle, opposite angles of the equal sides of the triangle will be equal in measure.

m∠2 = 53°

x + 65 = 53

x = 53 - 65

x = -12

7 0

2 years ago

PLEASE LOOK AT PHOTO! WHOEVER ANSWERS CORRECTLY I WILL MARK BRAINIEST!!

oee [108]

Answer:

x= 5

Step-by-step explanation:

As the mid-point of 2 and 8 is 5.

PLEASE MARK ME AS BRAINLIEST!

4 0

3 years ago

Read 2 more answers