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lakkis [162]
3 years ago
5

What are the real zeros y=(x+3)^3+10?

Mathematics
1 answer:
igomit [66]3 years ago
7 0
There is only 1
(x + 3)^3 + 10 = 0
(x + 3)^3 = - 10
(x + 3) = cuberoot(-10)
x = -3 + cuberoot(-10)
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Find the value of x'.<br> (7x - 22)<br> (3x+ 2)<br> X=<br><br> Need help please and quick
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X=6

Step-by-step explanation:

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given the to find the circumference is diameter by pi, so divide 3.5 by pi to get 1.11408460164 so.. 1.114?

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The Sahara Desert has an area of approximately 9,400,400 km2. While estimates of its average depth vary, they center around 150
dolphi86 [110]

Answer:

1.128048 \times 10^{25} grains of sand are in the Sahara Desert

Step-by-step explanation:

Given :

The Sahara Desert has an area of approximately 9,400,400 sq.km.

Depth = 150 m

To Find :Approximately how many grains of sand are in the Sahara Desert?

Solution:

Area of Sahara desert = 9,400,400 sq.km.

1 km^2 = 1000000 m^2

So, 9,400,400 km^2 = 1000000 \times 9400400 m^2

9,400,400 km^2 =9.4004 \times 10^{12}m^2

Volume of sand =Area \times depth

                           =1.41006\times 10^{15} m^3

1 m ^3 = 1000000 cm^3

So, 1.41006\times 10^{15} m^3 = 1.41006\times 10^{15} \times 1000000cm^3

1.41006\times 10^{15} m^3 =1.41006 \times 10^{21}cm^3

1 cubic cm holds grains of sand = 8000

1.41006 \times 10^{21}cm^3 holds grains of sand = 1.41006 \times 10^{21} \times 8000

                                                                                    = 1.128048 \times 10^{25}

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7 0
3 years ago
HELP please urgent!! - PLEASE CLICK, NEED HELP -
Makovka662 [10]

Answer:

y=3x^2-12x-135

Step-by-step explanation:

The standard form of a quadratic is  y=ax^2+bx+c

We will use the x and y values from each of our 3 points to find a, b, and c.  Filling in the x and y values from each point:

First point (-5, 0):

0=a(-5)^2+b(-5)+c and

0 = 25a - 5b + c

Second point (9, 0):

0=a(9)^2+b(9)+c and

0 = 81a + 9b + c

Third point (8, -39):

-39=a(8)^2+b(8)+c and

-39 = 64a + 8b + c

Use the elimination method of solving systems on the first 2 equations to eliminate the c.  Multiply the first equation by -1 to get:

-25a + 5b - c = 0

81a + 9b + c = 0

When the c's cancel out you're left with

56a + 14b = 0

Now use the second and third equations and elimination to get rid of the c's.  Multiply the second equation by -1 to get:

-81a - 9b - c = 0

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-17a - 1b = -39

Between those 2 bolded equations, eliminate the b's.  Do this by multiplying the second of the 2 by 14 to get:

56a + 14b = 0

-238a - 14b = -546

When the b's cancel out you're left with

-182a = -546 and

a = 3

Use this value of a to back substitute to find b:

56a + 14b = 0 so 56(3) + 14b = 0 gives you

168 + 14b = 0 and 14b = -168 so

b = -12

Now back sub in a and b to find c:

0 = 25a - 5b + c gives you

0 = 75+ 60 + c so

0 = 135 + c and

c = -135

Put that all together into the standard form equation to get

y=3x^2-12x-135

6 0
4 years ago
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