Answer:
The point for the given linear equations is (
, 
)
Step-by-step explanation:
Given as :
The two linear equations are
First equation
y = 
x + 5
Or, y + x + 5 = 0
Taking LCM we get
y + x + 10 = 0 .......1
Second equation
y = 2 x + 2 ........2
Now solving both equation
Putting the value of y from eq 2 into eq 1
(2 x + 2) + x + 10 = 0
Or, 3 x + 12 = 10
Or, 3 x = 10 - 12
Or, 3 x = - 2
∴ x =
Now putting the value of x into eq 2
∵ y = 2 x + 2
Or, y = 2 × + 2
Or, y = 
+ 2
Or, y = 
∴ y =
So, The points are (x , y ) = ( , )
Now, plotting the points on x-y coordinate graph
Hence, The point for the given linear equations is ( , ) Answer
The degree of a polynomial is the highest power anything is raised to. so x+3 is the same as x(^1) + 3
<span>so first degree. </span>
<span>x^2 +3 is a second degree</span>
Answer:
x = 21
Step-by-step explanation:
-7 ( x + 1 ) - 3 = -8x + 11
-7x - 7 - 3 = -8x + 11
x = 7 + 3 + 11
x = 21
<u>Answer:</u>
The correct answer option is (5, -6).
<u>Step-by-step explanation:</u>
We know that the following are the coordinates of a point:
If this point is reflected through y axis, we are to find the coordinates of its image?
If a point is reflected through y-axis, the sign of the x coordinate is changed so we get:
(5, -6)
Answer:
12, 1
Step-by-step explanation:
12- 6(1)=
12-6= 6
