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DIA [1.3K]
3 years ago
9

Quick Question!

Mathematics
2 answers:
masya89 [10]3 years ago
8 0

It is unidentifiable, because nothing can be divided by 0

Artemon [7]3 years ago
7 0

Answer:

Undefined

Step-by-step explanation:

13×27÷6+8-17÷0×45×67×0×334 would equal undefined because you are dividing by 0. Anything divided by 0 is undefined.

If this answer is correct, please make me Brainliest!

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Which of the following is not a linear equation? A. x-y=7 b. 0.5x-0.2y=7 c.5y^2=xy+2x d. 2x+y=4
vitfil [10]

Answer:

C

hope that helps!

please mark brainiest<3

4 0
3 years ago
What is the answer to <br> 1/4 - (-3/4)
Nookie1986 [14]

Answer:

1

Step-by-step explanation:

1/4+3/4 this makes a plus because a -&- makes +

1+3/4

4/4

1

4 0
2 years ago
Read 2 more answers
A deck of cards contains RED cards numbered 1,2,3,4,5, BLUE cards numbered 1,2,3, and GREEN cards numbered 1,2,3,4,5,6. If a sin
Tatiana [17]

Answer: 1/52

Step-by-step explanation:

A deck of cards contains 52 cards

Red cards are numbered 1,2,3

Blue cards are numbered 1,2,3,4,5,6

Green cards are numbered 1,2

Number of Red card = 3

Number of blue card = 6

Number of Green card = 2

Let Pr(R) = Probability of picking a Red card

Let Pr(B) = probability of picking a blue card

Let Pr(G) = probability of picking a green card

Let Pr(RE) = Probability of picking a red even card

Let Pr(RO) = probability of picking a red odd card

Let Pr(BE) =probability of picking a blue even card

Let Pr(BO) = probability of picking a blue odd card

Let Pr(GE) = probability of picking a green even card

Let Pr(GO) = probability of picking a green odd card

Pr(R) = 3/52

Since we have 3 red cards,

Pr(RE) = 1/3

Pr(RO) =2/3

Pr(B) = 6/52

= 3/26

Since we have 6 blue cards ,

Pr(BE) = 3/6

= 1/2

Pr(BO) = 3/6

= 1/2

Pr (G) = 2/52

= 1/26

Since we have 2 green cards,

Pr(GE) = 1/2

Pr(GO) = 1/2

The probability of picking a Green card and an odd green card is

Pr(G) n pr(GO)

1/26 * 1/2

= 1/52

5 0
3 years ago
A cart is coasting past Gordon. As it passes, he exerts a force on it. Whether the cart speeds up, slows down, or changes direct
Ksivusya [100]

Answer:

Direction

Step-by-step explanation:

Whether the car slows down or speeds up depends on the direction of the force applied, because if Gordon applied the force opposite the direction of the cart's movement, then the cart will slow down. If however, the force is applied in the direction of the carts movement, then the cart will speed up.

6 0
3 years ago
A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi
viktelen [127]

Answer:

Side length = \sqrt{\frac{A}{3} } cm ,   Height =  \frac{1}{2} \sqrt{\frac{A}{3} } cm  ,  Volume = \frac{A\sqrt{A}}{6\sqrt{3} }  cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

  1. y = \frac{A - x^{2} }{4x}

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( \frac{A - x^{2} }{4x} )

V =  \frac{Ax - x^{3} }{4}

To find max volume put V' = 0

So taking derivative equation becomes

\frac{A - 3 x^{2} }{4} = 0

A = 3 x^{2}

x^{2} = \frac{A}{3}

x = \sqrt{\frac{A}{3\\} }

put value of x in equation 1

y = \frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }  

y = \frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }

y = \frac{1}{2} \sqrt{\frac{A}{3} }

So the volume will be

V = x^{2} × y

Put values of x and y from equation 2 & 3

V = \frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )

V = \frac{A\sqrt{A}}{6\sqrt{3} }

8 0
3 years ago
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