Answer / Explanation:
195.200.0.0/16
Note: Class C address can not be assigned a subnet mask of /16 because class c address has 24 bits assigned for network part.
2ⁿ = number of subnets
where n is additional bits borrowed from the host portion.
2ˣ - 2 = number of hosts
where x represent bits for the host portion.
Assuming we have 195.200.0.0/25
In the last octet, we have one bit for the network
number of subnets = 2¹ =2 network addresses
number of host = 2⁷ - 2= 126 network addresses per subnets
Answer:
Total Memory= 4 KB = 4096 bytes = 32768 bits
Explanation:
<em><u>1. Data lines are 8 From D0 to D7</u></em>
so
Total memory at single address locations is 8 bits.
<em><u>2. Address lines are 12 (A0 to A11)</u></em>
There are 12 address lines but 3 out 12 are for selction of chip or memory bank.
so only 9 pins are there to address the locations on one chip.
Total No. of address locations on single chip = 2^9 = 512 locations
as 1 location is 1 byte so total memory of single chip is 512 bytes.
<u><em>3. Total Memory Bank </em></u>
There are total 3 selection pins for memory bank.
so
Total chips = 2^3 = 8.
<em><u>4. Total Memory </u></em>
Total size of 1 chip = 512 bytes
Total size of 8 chip = 8x512 bytes = 4096 bytes = 4096/1024 kb = 4 kb
<em>So total memory of system is 4 Kb = 4096 bytes = 32768 bits</em>
Answer:
The answer to this question is Yes it is possible
Explanation:
It can be done In the case where a special server is required in each network that would forward the request to the remote ARP(Address Resolution Protocol) server and will receive the response from the server and send it to the requesting host.So we conclude that we can do that hence the answer is Yes.
