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ivann1987 [24]
3 years ago
8

Ranges of IP address that anyone can use for their internal networks are known as ______.

Computers and Technology
2 answers:
Rama09 [41]3 years ago
8 0
Since no answer choices, have to deduce it is Private Networks
ratelena [41]3 years ago
5 0

Ranges of IP address that anyone can use for their internal networks are known as "private networks".

A private network is a system that utilizes private IP address space. Both, the IPv4 and the IPv6 determinations characterize private tending to ranges. These addresses are usually utilized for neighborhood (LANs) in private, office, and undertaking situations. Private IP address spaces were initially characterized with an end goal to defer IPv4 address weariness.

Private network addresses are not apportioned to a particular association and anybody may utilize these addresses without endorsement from a territorial Internet registry. Be that as it may, IP parcels tended to from them can't be directed through people in general Internet.

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Susan teaches many individuals and business professionals how, why, and the benefits and challenges to using social media. Of th
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Answer:

The answer is B: Ensuring consumer protection

Explanation:

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see the attachment..........

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Write, compile and test (show your test runs!) program that calculates and returns the fourth root of the number 81, which is 3.
lys-0071 [83]

Answer:

I am writing a JAVA program. Let me know if you want the program in some other programming language.

public class FourthRoot{ //class to calculate fourth root of 81

public static void main(String[] args) { //start of main() function body

   double square_root; //declares to hold the fourth root of 81

   double number=81; // number is assigned the value 81

/* calculates the fourth root of number using sqrt() method twice which means sqrt() of sqrt(). This is equivalent to pow(number,(0.25)) where pow is power function that computes the fourth root by raising the number 81 to the power of 0.25 which is 1/4 */

   square_root=Math.sqrt(Math.sqrt(number));

//displays the fourth root of 81 i.e. 3

     System.out.println("Fourth Root of 81 is "+ square_root); } }

Explanation:

The program is well explained in the comments given along with each statement of the program . Since it was the requirement of the program to user Math.sqrt() method so the fourth root of number= 81 is computed by taking the sqrt() of 81 twice which results in the fourth root of 81 which is 3.

So the first sqrt(81) is 9 and then the sqrt() of the result is taken again to get the fourth root of 81. So sqrt(9) gives 3. So the result of these two computations is stored in square_root variable and the last print statement displays this value of square_root i.e. the fourth root of number=81 which is 3.

Another way to implement the program is to first take sqrt(81) and store the result in a variable i.e. square_root. After this, again take the sqrt() of the result previously computed and display the final result.

public class FourthRoot{

   public static void main(String[] args) {

   double square_root;

   double number=81;

   square_root=Math.sqrt(number);

  System.out.println("Fourth Root of 81 is: "+ Math.sqrt(square_root)); } }

The program along with its output is attached in a screenshot.

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