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ANEK [815]
3 years ago
5

Isabela wants to modify one of her paragraphs. However, she does not find the command she needs in the Paragraph group. She know

s it is in the Paragraph dialog box. How can she open it?
She can click the editing button.
She can select the Align Text button.
She can select the Paragraph button.
She can click the arrow in the Paragraph group
Computers and Technology
2 answers:
cluponka [151]3 years ago
5 0

Answer:

Editing button

Explanation:

Editing is changing therefore if she wants to modify her work she would be changing it.

Hope that helped :)

Lilit [14]3 years ago
3 0

Answer:

She can click the arrow in the Paragraph group

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Extend to also calculate and output the number of 1 gallon cans needed to paint the wal. Hint: Use a math function to round up t
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Answer:

Here is the Python program:

import math #import math to use mathematical functions

height = float(input("Enter wall height (feet): ")) #prompts user to enter wall height and store it in float type variable height

width = float(input("Enter wall width (feet): ")) #prompts user to enter wall width and store it in float type variable width

area = height *width #computes wall area

print('Wall area: {} square feet'.format(round(area))) #displays wall area using round method that returns a floating-point number rounded

sqftPerGallon = 350 #sets sqftPerGallon to 350

paintNeeded = area/ sqftPerGallon #computes needed paint

print("Paint needed: {:.2f} gallons".format(paintNeeded)) #displays computed paint needed up to 2 decimal places

cansNeeded = int(math.ceil(paintNeeded)) #computes needed cans rounding the paintNeeded up to nearest integer using math.ceil

print("Cans needed: {} can(s)".format(cansNeeded)) #displays computed cans needed

colorCostDict = {'red': 35, 'blue': 25, 'green': 23} #creates a dictionary of colors with colors as key and cost as values

color = input("Choose a color to paint the wall: ") #prompts user to enter a color

if color in colorCostDict: #if the chosen color is present in the dictionary

    colorCost = colorCostDict.get(color) #then get the color cost from dictionary and stores it into colorCost using get method that returns the value(cost) of the item with the specified key(color)

    cost = cansNeeded * colorCost #computes the cost of purchasing paint of specified color per cansNeeded

  print("Cost of purchasing {} paint: ${}".format(color,colorCostDict[color])) #displays the real cost of the chosen color paint

print("Cost of purchasing {} paint per {} gallon can(s): ${}".format(color,cansNeeded, cost)) #displays the cost of chosen color paint per cans needed.

Explanation:

The program first prompts the user to enter height and width. Lets say user enter 20 as height and 50 as width so the program becomes:

Wall area computed as:

area = height *width

area = 20 * 50

area = 1000

Hence the output of this part is:

Wall area: 1000 square feet                                                                                                                     Next program computes paint needed as:

paintNeeded = area/ sqftPerGallon

Since sqftPerGallon = 350 and area= 1000

paintNeeded = 1000 / 350

paintNeeded = 2.86

Hence the output of this part is:

Paint needed: 2.86 gallons

Next program computes cans needed as:      

cansNeeded = int(math.ceil(paintNeeded))

This rounds the computed value of paintNeeded i.e. 2.86 up to nearest integer using math.ceil so,

cansNeeded = 3                                                                  

Hence the output of this part is:

Cans needed: 3 can(s)                                                                                                                            Next program prompts user to choose a color to paint the wall

Lets say user chooses 'blue'

So the program get the cost corresponding to blue color and multiplies this cost to cans needed to compute the cost of purchasing blue paint per gallon cans. So

cost = cansNeeded * colorCost

cost = 3 * 25

cost = 75

So the output of this part is:

Cost of purchasing blue paint per 3 gallon can(s): $75                                                                                        The screenshot of the program along with its output is attached.

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