Answer:
Round-Robin DNS
Explanation:
According to my experience in Information Technology and Networking it can be said that based on the information provided the best solution would be to set up a Round-Robin DNS. This term refers to a technique used to balance the load on a server, where a client request is sent to each server one at a time, and then the system repeats the process from the top of the request list. This prevents the server from being drowned in a sea of simultaneous requests.
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Money Transfer.
HOPE THIS HELPS!
Answer:
import java.util.Scanner;
public class LabProgram {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int inputYear;
boolean isLeapYear;
isLeapYear = false;
inputYear = scnr.nextInt();
// If a year is divisible by 400, then it is a leap year
if (inputYear % 400 == 0)
isLeapYear = true;
// If a year is divisible by 100, then it is not a leap year
if (inputYear % 100 == 0)
isLeapYear = false;
// If a year is divisible by 4, then it is a leap year
if (inputYear % 4 == 0)
isLeapYear = true;
if(isLeapYear)
System.out.println(inputYear + " is a leap year.");
else
System.out.println(inputYear + " is not a leap year.");
}
}
Explanation:
- Take the year as an input from user and store it to inputYear variable.
- If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ), then set the boolean isLeapYear to true. If a year is divisible by 100, then set the boolean isLeapYear to false. If a year is divisible by 4, then set the boolean isLeapYear to true.
- Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.
Output:
1712
1712 is a leap year.
Answer:
The solution code is written in Python:
- mystery_string = "Programming"
- output = ""
-
- for x in mystery_string:
- output += x
- print(output)
Explanation:
Firstly, create a variable mystery_string to hold a random string (Line 1).
Create an output variable to hold an output string (Line 2).
Create a for-loop to traverse the mystery_string character by character (Line 4). In the iteration, get a character from the mystery_string, and concatenate it with output string (Line 5). Print the output string (Line 6) before proceed to the next iteration.
Answer:
i dont know.prob guess a short loop.
Explanation:
