Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
one solution
Step-by-step explanation:
3x − 7 = 4 + 6 + 4x
Combine like terms
3x-7=4x+10
Subtract 3x from each side
-7=x+10
Subtract 10 from each side
-17 =x
There is one solution
Hi there! The answer to this problem would be 36.64$.
Step By Step:
So there is three teachers and they all brought something.
_____________________________________
| Mrs.Maiers | 7.68$ |
| Mr.Lang | 11.52$ |
| Mrs.Connor | 17.64$ |
______________________________________
Total Cost: 36.64
It’s actually true!
^ ^ ^ ^
<—|——|——|——|——|—>
-2 -1 0 1 2
The 4 arrows above the number line represents the distance between 2 and -2 which is 4!
- Answer=9.7
Step-by-step explanation:
<h3>divide 19.4 by 2</h3>
