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mestny [16]
3 years ago
9

I need an equation that equals 18

Mathematics
2 answers:
IgorC [24]3 years ago
8 0
<span>16 + 2 = 18,
12+ 5=18,
20-2 =18 ,
9X2=18,

 there can be many equations .....
try them ...

Hope it helps !!!</span>
Oduvanchick [21]3 years ago
8 0

Answer:

Step-by-step explanation:

There can be an infinite number of equations that equals 18.

Let us try this as a straight line in a coordinate plane

x+y =18

This solution will be all the points on the line whose x and y coordinates add up to 18

Example:

(1,17)(2,16)(0,18)(-1,19) and so on.  i.e. all the points on the line.

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HELP PLEASE! DUE TMR! Answer whichever ones you want and i can try to deal with the rest. I just have alot of work and need extr
Yuri [45]

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1) 4

2) 0, 2, -10

3) 0, 5, -2

Step-by-step explanation:

1) x³ - 64 = 0

x³ = 64

x = 4

2) x³(x² + 8x - 20) = 0

x³(x² + 10x - 2x - 20) = 0

x³(x(x + 10) - 2(x + 10)) = 0

x³(x + 10)(x - 2) = 0

x = 0, 2, -10

3) x³ - 3x² - 10x = 0

x(x² - 3x - 10) = 0

x(x² - 5x + 2x - 10) = 0

x(x(x - 5) + 2(x - 5)) = 0

x(x - 5)(x + 2) = 0

x = 0, 5, -2

4 0
3 years ago
Which is the graph of a logarithmic function?
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Answer:

Answer is the first choice.

Step-by-step explanation:

A logarithmic graph is the opposite of an exponential growth graph, so the first option is the only one that fits. Just took the test and the first choice is correct.

6 0
3 years ago
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Solve the quadratic equation. Write your solutions in the blanks, starting with the smaller value.
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Answer:

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Step-by-step explanation:

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8 0
3 years ago
New codes to destroy the First Order are known to exist. With probability 0.6, the codes are hidden by Leia; with probability 0.
elixir [45]

Answer: (a). 0.62 (b). 0.53

Step-by-step explanation:

Let us start by defining some events seen:

Given;

L rep the event that codes hidden Leia

BB represents the codes hidden in BB-8

H is the event that codes hidden by Hah

C-3PO rep the codes hidden in C3PO

Giving the probabilities, we have that

P(L)  =  probability that codes are hidden by Leia = 0.6

P(H) = probability that codes are hidden by Hah = 0.4

where P(BB/L) = 70/10 i.e 70%

P(C-3PO/L) = 1 - P(BB/L) = 1 - 7/10 = 3/10

Also, P(BB/H)  = 1/2 = P(C-3PO/H)

We can say that Han Solo is likely to hide them in aceta BB-8 and C-3PO

To begin,

(a). The question tell us to find the probability that the codes are with BB-8.

First of all, we find P(BB).

P(BB) = P(L)*P(BB/L) + P(H)*P(BB/H)

solving this we get

P(BB) = 0.6*7/10 + 0.4*1/2 = 0.62

Therefore,  the probability that the codes are with BB-8 = 0.62

(b). The second question says;

Given that the codes are with C-3PO, what is the probability the codes were hidden by Han Solo?

This tell us to find P(H/C-3PO)

P(H/C-3PO) = P(C-3PO/H)*P(H) / P(C-3PO/H) + P(C-3PO/L)*P(L)

inputting the values gives us;

P(H/C-3PO) = 1/2 * 0.4 / ( 1/2 *0.4 + 3/10 *0.6) = 0.53

SO we have that the probability the codes were hidden by Han Solo = 0.53

cheers I hope this was helpful!!

3 0
3 years ago
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