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galina1969 [7]
4 years ago
14

One sector in the diagram is: IKLV YTXK ULYK XKIY

Mathematics
1 answer:
lara31 [8.8K]4 years ago
3 0

Answer:

The sector of the given circle is IKLV

Step-by-step explanation:

Given as :

The figure shown is the circle

The circle have chord as UT and VT

Both chords UT and VT meets at points T outsides the circle , and intersect the circle at Y and I

Now,

Points L and I are on the circle with center K

The line is drawn joining center K and point L as KL which is the radius

The line is drawn joining center K and point I as KI which is the radius

Now, A sector is the area enclosed by two radius and arc

So, here KL and KI are two radius and LI is the arc

So, IKLV is the sector

Hence the sector of the given circle is IKLV  . Answer

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Answer:

Yes since the triangles are congruent by ASA. See proofs and explanation below.

Step-by-step explanation:

The cardio and free weights will have the same amount of space because triangles ABE and BCE are congruent by ASA or Angle-Side-Angle. We know that angle AEB and angle DEC are congruent since they are vertical angles. This is the first angle is ASA. We also know that the two triangles must be congruent because line segment DE is congruent to line segment EB since E is the midpoint of DB. This is the side in ASA. Lastly, the other angle of ASA can be proven because AB and DC are parallel lines. SInce they are parallel they have special angle relationships when the transversal DB intersects them. Since angle ABE and angle EDC are alternate interior angles, they are congruent. This means the triangles must be congruent. When triangles are congruent, then each triangle is the same shape and size. This means their area is the same too. Therefore, cardio and free weights have the same amount of space.

To write a two columns proof, start with given information, add new information, and then conclude.

Statement                                            Reason

1. AB ║CD                                                 Given

2. E midpoint of DB                                  Given

3. DE ≅ EB                                                 Definition of Midpoint

4.  ∠ABE≅∠EDC                                        Alternate Interior Angles

5.  ∠AEB ≅ ∠DEC                                      Vertical Angle Theorem

6. ΔABE≅ΔCDE                                          ASA


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Step-by-step explanation:

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