If the perimeter of equilateral triangle is 77 and the equation showing the perimeter is 6.5X-1 then the value of X is equal to 12.
Given that the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1.
We are required to find the value of X which is used in the expression.
Expression is combination of numbers, fraction, coefficients, indeterminants, determinants, which are mostly not found in equal to form.
Perimeter which is given is 77 and 6.5X-1.
6.5X-1=77
6.5X=77+1
6.5X=78
X=78/6.5
X=12
Hence if the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1 then the value of X is equal to 12.
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The relationship between lines KO and K’O’ is given as Line K'O' = 5 * line KO
<h3>What is a
transformation?</h3>
Transformation is the movement of a point from its initial point to a new location. Types of transformation are<em> reflection, rotation, translation and dilation.</em>
Dilation is the increase or decrease in size of a figure by a scale factor.
The larger figure was dilated using a scale factor of 5, hence:
Line K'O' = 5 * line KO
The relationship between lines KO and K’O’ is given as Line K'O' = 5 * line KO
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Answer: the correct answer is 9(x2+6x+9)=103 so it’s d
Step-by-step explanation:
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Answer:
33/400
Step-by-step explanation:
0.0825=825/10000
=165/2000
=33/400
Answer:
x + 2y = 8.
Step-by-step explanation:
Line goes through (-4, 0) and (4, -4).
The slope is (-4 - 0) / (4 - -4) = -4 / (4 + 4) = -4 / 8 = -1/2.
Since we are looking for the equation of the line parallel to that line, the slope will be the same.
We have an equation of y = -1/2x + b. We have a point at (2, 3). We can then say that y = 3 when x = 2.
3 = (-1/2) * 2 + b
b - 1 = 3
b = 4.
So, we have y = -1/2x + 4.
1/2x + y = 4
x + 2y = 8.
Hope this helps!
