Round to the nearest ten thousand 905154

1 answer:

5 0

You want to round 905,154 to the nearest ten-thousands place. The ten-thousands place in your number is shown by the bold underlined digit here:

905,154

 To round 905,154 to the nearest ten-thousands place...

 The digit in the ten-thousands place in your number is the 0. To begin the rounding, look at the digit one place to the right of the 0, or the 5, which is in the thousands place.

 Since the 5 is greater than or equal to 5, we'll round our number up by

 Adding 1 to the 0 in the ten-thousands place, making it a 1.

 and by changing all digits to the right of this new 1 into zeros.

The result is: 910,000.

So, 905,154 rounded to the ten-thousands place is 910,000.

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To prove ∆LMN ≅ ∆PQR by SSS you need _______________ and ______________ and ______________

Elis [28]

Given:

To prove ∆LMN ≅ ∆PQR by SSS you need _____________ and

_______________ and ______________.

To find:

The missing values.

Solution:

If ∆LMN ≅ ∆PQR by SSS, then all sides of ∆LMN are congruent to corresponding sides of ∆PQR.

$LM\cong PQ$

$MN\cong QR$

$LN\cong PR$

Therefore, the missing values are $LM\cong PQ, MN\cong QR,LN\cong PR$ .

6 0

3 years ago

I need help with this ASAP!

earnstyle [38]

Answer and Step-by-step explanation:

1) If you graph the lines, you will get the lines in the first attachment. You will see that the intersection point is (3, 5), which is the solution to that system.

2) First, let's convert both of these into slope-intercept form so that they're easier to graph.

x - 3y = 2

x = 3y + 2

3y = x - 2

y = $\frac{1}{3}x-\frac{2}{3}$

AND

-3x + 9y = -6

9y = 3x - 6

y = $\frac{3}{9} x-\frac{6}{9} =\frac{1}{3} x-\frac{2}{3}$

We see that these two lines are exactly the same, which means that no matter what coordinate works for one, it will work for the other. In other words, there are infinitely many solutions.

And, if you graph these lines, you will get the graph in the second attachment, where they are the same line.

Hope this helps!