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mestny [16]
3 years ago
15

Which are the roots of the quadratic function f(b) = 62 – 75? Select two options.

Mathematics
1 answer:
elena55 [62]3 years ago
4 0

Answer:

b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

Step-by-step explanation:

Given

f(b) = b^2 - 75

Required

Determine the roots

To get the root of the function, then f(b) must be 0;

i.e. f(b) = 0

So, the expression becomes

0 = b^2 - 75

Add 75 to both sides

75 + 0 = b^2 - 75 + 75

75 = b^2

Take square roots of both sides

\sqrt{75} = \sqrt{b^2}

\sqrt{75} = b

Reorder

b = \sqrt{75}

Expand 75 as a product of 25 and 3

b = \sqrt{25*3}

Split the expression

b = \sqrt{25} *\sqrt{3}

b = \±5 *\sqrt{3}

b = \±5 \sqrt{3}

b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

The options are not clear enough; however the roots of the equation are b = 5 \sqrt{3} \ or\ b = -5 \sqrt{3}

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