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sleet_krkn [62]
3 years ago
7

It is time my friends...please help me with this image that has haunted me

Mathematics
2 answers:
trasher [3.6K]3 years ago
8 0

Answer:

C, 7 1/2

Step-by-step explanation:

12 is 2/3 of 18, therefore 5 is 2/3 of something, so you divide 5 by 2/3 which is 15/2 which is 7 1/2

GaryK [48]3 years ago
5 0

Answer: C

7 and 1/2"

Step-by-step explanation:

First, let's figure out what 12 is being multiplied by to get 18. To do this, we divide 18 by 12. We get 1.5. Now, to find x we multiply 5 by 1.5.

5 times 1.5 = 7.5 (AKA 7 and 1/2)

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Step-by-step explanation:

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2 years ago
Simplify x + 4 - 5x - 2.
Ilia_Sergeevich [38]
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2 years ago
two-point charges are 10.0 cm apart and have charges of 2.0 uc and -2.0uc respectively What is the magnitude of the electrical f
maks197457 [2]

Answer:

The electric field generated by a point charge is given by:

where

is the Coulomb's constant

Q is the charge

r is the distance from the charge

We want to know the net electric field at the midpoint between the two charges, so at a distance of r=5.0 cm=0.05 m from each of them. 

Let's calculate first the electric field generated by the positive charge at that point:

where the positive sign means its direction is away from the charge.

while the electric field generated by the negative charge is:

where the negative sign means its direction is toward the charge.

If we assume that the positive charge is on the left and the negative charge is on the right, we see that E1 is directed to the right, and E2 is directed to the right as well. This means that the net electric field at the midpoint between the two charges is just the sum of the two fields:

Read more on Brainly.com - brainly.com/question/9699355#readmore

Step-by-step explanation:

6 0
3 years ago
How would I solve this Rational Equation? <br><br>Solve for all values of x.
Nesterboy [21]

9514 1404 393

Answer:

  x = 4

Step-by-step explanation:

I like to put these in the form f(x) = 0. We can do that by subtracting the right side. Common factors can be cancelled from numerator and denominator, provided they are not zero.

  \dfrac{7}{x+3}+\dfrac{3}{x-3}-\dfrac{x}{x-3}=0\\\\ \dfrac{7(x-3)+(x+3)(3-x)}{(x+3)(x-3)}=0\\\\\dfrac{(x-3)(4-x)}{(x-3)(x+3)}=0\\\\ \dfrac{4-x}{x+3}=0\qquad x\ne3\\\\x=4 \qquad\text{equate the numerator to zero, add $x$}

_____

If you leave the numerator as (x-3)(4-x), then there are two values of x that make it zero. Because x=3 makes the equation "undefined", it cannot be considered to be a solution.

4 0
3 years ago
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