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xenn [34]
3 years ago
12

What is the rate he charges to mow?

Mathematics
1 answer:
Ainat [17]3 years ago
6 0
The rate he charges to mow is gonna be d
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The lemonade stand at the county fair sells the lemonade at a price of two cups for $3.60. Complete the table at right to find w
kakasveta [241]
$3.60 for 2 cups would be $1.80 for one cup.

$3.60 for 2

$5.40 for 3

$7.20 for 4

$9 for 5

$10.80 for 6

$12.60 for 7

$14.40 for 8



4 0
3 years ago
Combine the like terms of the expression (8 + 6x) + (-4 + 9c). Explain how you simplified the expression in each step. * pls hel
Delicious77 [7]

Answer: 6x+9c+4

Step-by-step explanation:  (8 + 6x) + (-4 + 9c)

                                              8+6x-4+9c

                                              6x+9c+8-4

                                              6x+9c+4

8 0
3 years ago
Let X be a continuous random variable with density functionf(x)={1−|x|0 for −1
BlackZzzverrR [31]

Answer:

f_Y (y) =\frac{d}{dy} = 2 \frac{1}{2 |\sqrt{y}|} -1 = \frac{1}{|\sqrt{y}|} -1,0 \leq Y\leq 1

Step-by-step explanation:

For this case we want to find the density function for Y=X^2

And we have the following density function for the random variable X:

f(X) = 1- |X|,-1 \leq X \leq 1

So we can do this replacing Y=X^2

F_Y (Y \leq y) = P(X^2 \leq y)

If we apply square root on both sides we got:

P(-\sqrt{y} \leq X \leq \sqrt{y}) = \int_{-\sqrt{y}}^0 1+t dt +\int_{0}^{\sqrt{y}} 1-t dt

And if we integrate we got this:

F_Y (y) = [t+ \frac{t^2}{2}] \Big|_{-\sqrt{y}}^0+ [t -\frac{t^2}{2}] \Big|_{0}^{\sqrt{y}}

And replacing we got:

F_Y (y) = [0 -(-\sqrt{y} +\frac{y}{2})] + [\sqrt{y} -\frac{y}{2}]

F_Y (y) = 2 |\sqrt{y}| -y

And if we want to find the density function we just need to derivate the pdf like this:

f_Y (y) =\frac{d}{dy} = 2 \frac{1}{2 |\sqrt{y}|} -1 = \frac{1}{|\sqrt{y}|} -1,0 \leq Y\leq 1

3 0
4 years ago
A satellite in a circular orbit 1250 kilometers above Earth makes one complete revolution every 110 minutes. What is its linear
Ivenika [448]

Answer:

\large \boxed{\text{approximately 435.7 km/min}}  

Step-by-step explanation:

1. Angular speed

The angular speed ω is the angle θ swept out by the satellite in a given time t.

\omega = \dfrac{\theta}{t} = \dfrac{2\pi}{\text{110 min}}

2. Linear speed

The formula for the linear speed v is

v = rω, where

r = the distance from the centre of the Earth = 6378 km + 1250 km = 7628 km

\begin{array}{rcl}v & = & r\omega\\& = & \text{7268 km} \times \dfrac{2\pi}{\text{110 min}}\\\\& \approx & \textbf{435.7 km/min}\\\end{array}\\\text{The linear speed of the satellite is $\large \boxed{\textbf{approximately 435.7 km/min}}$}

7 0
3 years ago
Can someone please explain this to me? I don't get it​
alina1380 [7]
A straight line is equal to 180, anything going all around is 360 if the angles are crossing eachother then the angles across from eachother are equal so x=z
X+150=180, Im not good at explaining sorry, but i know what I’m doing yk just lmk sorry if it didn’t help
8 0
3 years ago
Read 2 more answers
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