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Firdavs [7]
3 years ago
5

2 sec (4x) - 2

Mathematics
1 answer:
ankoles [38]3 years ago
5 0

Answer:

Step-by-step explanation:

Find the limit of x to 0 of 4•Sec(4x)^-2

We know that, Sec4x = 1 / Sin4x

Then,

Lim x → 0: 4•(1 / Sin4x)^-2

Lim x → 0: 4•(Sin4x)²

Then,

Lim x → 0: 4(Sin(4×0))²

Lim x → 0: 4(Sin0)²

Lim x → 0: 4

Then, the limit as x → 0 is 4.

The correct answer is 4

Option A

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Now both triangles are 30^\circ-60^\circ-90^\circ, which means there's a convenient ratio between its sides. If the length of the shortest leg is \ell_1, then the length of the longer leg is \ell_2=\sqrt3\ell_1 and the hypotenuse has length \ell_3=\sqrt{{\ell_1}^2+{\ell_2}^2}=2\ell_1.

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Answer:

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3 years ago
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