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olga2289 [7]
2 years ago
15

3 miles below sea level

Mathematics
1 answer:
vlada-n [284]2 years ago
8 0

Answer:

the answer would be -3 since it's below.

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YOULL GET BRAINLIEST
soldier1979 [14.2K]

Answer:

Parent Function: y = x^2

Vertex: (1,3)

Axis of Symmetry: x = 1

Y-Intercept(s): (0,1)

X-Intercept(s): (1−√62,0),(1+√62,0)

Step-by-step explanation:

hope this helps! =)

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2 years ago
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mylen [45]

Answer:

QF=gR

F=gR/Q

Step-by-step explanation:

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2 years ago
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in 2011, an Action Comics no. 1, featuring first appearance of superman, was sold at auction for $2,161,000. The comic book was
Salsk061 [2.6K]

Price of book in 1938 = $ 0.10

Price of book in 2011 = $ 2,161,000

Number of years over 1938-2011 = 2011 - 1938 = 73

Annual increase in the price = ((\frac{\text{Price of book in 2011}}{\text{Price of book in 1938}}) ^ \frac{1}{\text{Number of years}} - 1 ) * 100

⇒ Annual increase in the price = ((\frac{2,161,000}{0.1}) ^ \frac{1}{73} - 1 ) * 100

⇒ Annual increase in the price = (1.260302283  - 1 ) × 100

⇒ Annual increase in the price = 0.260302283 × 100

⇒ Annual increase in the price = 26.0302283 %

⇒ Annual increase in the price = 26%

Hence, the comic book price increased by 26% annually

3 0
3 years ago
A teacher asked 4 students to estimate the weight of 4 different objects. The table shown represents their estimates. Which stud
balandron [24]
student one has the largest percent error.
3 0
3 years ago
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PLEASE HELP ME
denis23 [38]

Answer:

(1) The possible outcomes are: X = {0, 1, 2, 3}.

(2) The number of times should Hartley spin a difference of 1 is 36.

(3) The number of times should Hartley spin a difference of 0 is 24.

Step-by-step explanation:

The number of sections on the spinner is 4 labelled as {1, 2, 3, 4}.

The total number of spins for each of the spinner is, <em>n</em> = 96.

(1)

The sample space of spinning both the spinners together are:

S = {(1, 1), (1, 2), (1, 3), (1, 4)

      (2, 1), (2, 2), (2, 3), (2, 4)

      (3, 1), (3, 2), (3, 3), (3, 4)

      (4, 1), (4, 2), (4, 3), (4, 4)}

Total = 16.

The possible outcomes are:

X = {0, 1, 2, 3}.

(2)

The sample space with the difference 1 are:

S₁ = {(1, 2), (2, 1), (2, 3), (3, 2), (3, 4), (4, 3)}

n (S₁) = 6

The probability of the difference 1 is:

P(\text{Diff}=1)=\frac{n(S_{1})}{N}=\frac{6}{16}=\frac{3}{8}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 1 is:

E(\text{Diff}=1)=P(\text{Diff}=1)\times n\\\\=\frac{3}{8}\times 96\\\\=36

Thus, the number of times should Hartley spin a difference of 1 is 36.

(3)

The sample space with the difference 0 are:

S₂ = {(1, 1), (2, 2), (3, 3), (4, 4)}

n (S₂) = 4

The probability of the difference 0 is:

P(\text{Diff}=0)=\frac{n(S_{2})}{N}=\frac{4}{16}=\frac{1}{4}

The spinners were spinner 96 times.

The expected number of times would Hartley spin a difference of 0 is:

E(\text{Diff}=0)=P(\text{Diff}=0)\times n\\\\=\frac{1}{4}\times 96\\\\=24

Thus, the number of times should Hartley spin a difference of 0 is 24.

4 0
3 years ago
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