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sergey [27]
3 years ago
10

Factor out the coefficient of the variable: 2/9j + 2/3

Mathematics
2 answers:
baherus [9]3 years ago
7 0
To factor out 2/9, we must find how it factors out of 2/3. Divide 2/3 by 2/9, which is the same as multiplying ⅔ and 9/2, then you get (2*9)/(2*3) or 9/3 which is 3. So factored out the expresssion looks like 2/9(j+3)
Valentin [98]3 years ago
6 0
Factorisation:

2/9j+2/3

=2/9j+6/9

=2/9(j+3)
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Step-by-step explanation:

As we know that

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The perpendicular bisector of the line segment joining the points (1, 1) and (1, 3) will be:

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The perpendicular bisector of the line segment joining the points (1, 3), and (9, 2) will be:

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These intersect at the center of the circle (5, 2).

The distance between (1, 1) and (5, 2) will be:

\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

\mathrm{The\:distance\:between\:}\left(1,\:1\right)\mathrm{\:and\:}\left(5,\:2\right)\mathrm{\:is\:}

=\sqrt{\left(5-1\right)^2+\left(2-1\right)^2}

=\sqrt{4^2+1}

=\sqrt{16+1}

=\sqrt{17}

So the equation of the circle can be written as:

\left(x-5\right)^2+\left(y-2\right)^2=17

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3 years ago
Pls help!!!! will give brainliest
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Step-by-step explanation:

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