9514 1404 393
Answer:
C. The zeros are -1 and 5/2, because f(x) = (x + 1)(2x-5).
Step-by-step explanation:
The zeros of the function are the values that make the factors zero. The factors need to multiply out to give the original standard-form equation.
The sign of the constant (-5) tells you the product of the constants in the factors must be -5. That is only true for choices B and C.
Additionally, the x-term needs to match the result of multiplying out the factors.
B. (x -1)(2x +5) = 2x^2 +3x -5 . . . . . . . . . wrong x-term (not -3x)
C. (x +1)(2x -5) = 2x^2 -3x -5 . . . . . . . . . matches the given f(x)
The factors of C are zero when x=-1, x=5/2.
The formula for the nth term of a geometric sequence:

a₁ - the first term, r - the common ratio
![54, a_2, a_3, 128 \\ \\ a_1=54 \\ a_4=128 \\ \\ a_n=a_1 \times r^{n-1} \\ a_4=a_1 \times r^3 \\ 128=54 \times r^3 \\ \frac{128}{54}=r^3 \\ \frac{128 \div 2}{54 \div 2}=r^3 \\ \frac{64}{27}=r^3 \\ \sqrt[3]{\frac{64}{27}}=\sqrt[3]{r^3} \\ \frac{\sqrt[3]{64}}{\sqrt[3]{27}}=r \\ r=\frac{4}{3}](https://tex.z-dn.net/?f=54%2C%20a_2%2C%20a_3%2C%20128%20%5C%5C%20%5C%5C%0Aa_1%3D54%20%5C%5C%0Aa_4%3D128%20%5C%5C%20%5C%5C%0Aa_n%3Da_1%20%5Ctimes%20r%5E%7Bn-1%7D%20%5C%5C%0Aa_4%3Da_1%20%5Ctimes%20r%5E3%20%5C%5C%0A128%3D54%20%5Ctimes%20r%5E3%20%5C%5C%0A%5Cfrac%7B128%7D%7B54%7D%3Dr%5E3%20%5C%5C%20%5Cfrac%7B128%20%5Cdiv%202%7D%7B54%20%5Cdiv%202%7D%3Dr%5E3%20%5C%5C%0A%5Cfrac%7B64%7D%7B27%7D%3Dr%5E3%20%5C%5C%0A%5Csqrt%5B3%5D%7B%5Cfrac%7B64%7D%7B27%7D%7D%3D%5Csqrt%5B3%5D%7Br%5E3%7D%20%5C%5C%0A%5Cfrac%7B%5Csqrt%5B3%5D%7B64%7D%7D%7B%5Csqrt%5B3%5D%7B27%7D%7D%3Dr%20%5C%5C%0Ar%3D%5Cfrac%7B4%7D%7B3%7D)
189 inches is 15.75 feet
16 ft - 15.75 ft = 0.25 ft
0.25ft = 3 inches
He must vault 3 inches higher
$65.91 should be the account balance at the end of the month