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alekssr [168]
3 years ago
14

ron has 2500 pounds of sod to deliver. He wants to deliver an equal amount of sod on each 4 trips. write an equation for s the a

mount of sod that ron should deliver on each trip then solve equation for s
Mathematics
1 answer:
Rama09 [41]3 years ago
6 0
4s= 2500.  2500 divided by 4 equals 625 
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Find the equation of the line that passes through point A (1,7) and B (-3, -1)
amid [387]

Answer:

The equation of the line is 2 x - y + 5 = 0.

Step-by-step explanation:

Here the given points are A( 1, 7) & B( -3, - 1) -

Equation of a line whose points are given such that

( x_{1}, y_{1} ) & ( x_{2}, y_{2} )-

 y - y_{1}  = \frac{ y_{2} - y_{1} }{ x_{2} - x_{1} }   ( x - x_{1}  )

i.e. <em> y - 7= \frac{- 1 - 7}{ -3-1}  ( x- 1)</em>

<em>       y - 7 =  \frac{- 8}{- 4} ( x -1)</em>

<em>       y - 7 =  2 ( x - 1) </em>

<em>       y - 7  =   2  x - 2</em>

<em>       2 x - y + 5 = 0</em>

Hence the equation of the required line whose passes trough the points ( 1, 7) & ( -3, -1)  is 2 x - y  + 5 = 0.

6 0
3 years ago
A water park sold 14 child tickets and 6 adult tickets. What percentage of
steposvetlana [31]
Total tickets sold :
14 + 6 = 20

fraction of child tickets sold = 14/20

then, we convert this fraction to %.

14/20 = 70/100
( multiply by 5 )

percentage = 70%
5 0
2 years ago
Read 2 more answers
What is the following product? <br>(4x square root 5x^2 + 2^2 square root 6)^2​
tangare [24]

The product is 104 x^{4}+16 \sqrt{30} x^{4}

Explanation:

The given expression is \left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}

We need to determine the product of the given expression.

First, we shall simplify the given expression.

Thus, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x \sqrt{5} x+2 x^{2} \sqrt{6}\right)^2

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)^2

Expanding the expression, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)\left(4 x^{2} \sqrt{5}+2 x^{2} \sqrt{6}\right)

Now, we shall apply FOIL, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=\left(4 x^{2} \sqrt{5}\right)^{2}+2 ( 2 x^{2} \sqrt{6})(4 x^{2} \sqrt{5})+\left(2 x^{2} \sqrt{6}\right)^{2}

Simplifying the terms, we have,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=16 \cdot 5 x^{4}+16 \sqrt{30} x^{4}+4 \cdot 6 x^{4}

Multiplying, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=80 x^{4}+16 \sqrt{30} x^{4}+24 x^{4}

Adding the like terms, we get,

\left(4 x \sqrt{5 x^{2}}+2 x^{2} \sqrt{6}\right)^{2}=104 x^{4}+16 \sqrt{30} x^{4}

Thus, the product of the given expression is 104 x^{4}+16 \sqrt{30} x^{4}

7 0
3 years ago
Please help!!!!!!!!!
Natali [406]

Answer: $432

Step-by-step explanation: If he marks up the price by 80% then you multiply the price (240) times 0.8, which is 192. That is how much he marks it up -- $192. SO then you add how much he marks it up to the original price of $242 which is $432.

6 0
3 years ago
If the area of AABC is D, give the expressions that complete the equation for the measure of ZB?
Ira Lisetskai [31]

Given:

The figure of triangle ABC.

The area of the triangle ABC is D.

m\angle B=\sin ^{-1}(\dfrac{m}{n})

To find:

The value of m and n in the given expression.

Solution:

Let h be the height of the triangle ABC.

Area of a triangle is:

Area=\dfrac{1}{2}\times base\times h

Where, b is the base and h is the height of the triangle.

Area=\dfrac{1}{2}\times a\times h

The area of the triangle ABC is D.

D=\dfrac{1}{2}\times a\times h

2D=ah

\dfrac{2D}{a}=h                  ...(i)

In a right angle triangle,

\sin \theta =\dfrac{Perpendicular}{Hypotenuse}

\sin B =\dfrac{h}{c}

\sin B =\dfrac{1}{c}\times \dfrac{2D}{a}              [Using (i)]

\sin B =\dfrac{2D}{ac}

m\angle B =\sin ^{-1}\dfrac{2D}{ac}            ...(ii)

We have,

m\angle B=\sin ^{-1}(\dfrac{m}{n})          ...(iii)

On comparing (ii) and (iii), we get

m=2D

n=ac

Therefore, the required values are m=2D, n=ac.

6 0
3 years ago
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