2 years ago

How do I solve inequalities with fractions on both sides?

Mathematics

1 answer:

KIM [24]2 years ago

6 0

Please comment if you have any questions... :)

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35 POINTS. I need help! Please!

topjm [15]

There is no solution for the first one

if you eliminate y you get 2 equations
-13x - 13z = -25
-13x - 13x = -15

- there is no solution to theses

a23 means the element in the second row and the 3rd column

so its -5

7 0

3 years ago

1.) -9x+8 ≤ 80 * A. x ≥ -8 B. x ≤ -8 C. x ≥ 8 D. x ≤ 8

Firlakuza [10]

Answer:

$x\geq -8$

Step-by-step explanation:

$-9x+8\leq 80$

-8 -8

₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋₋

$\frac{-9x}{-9} \leq \frac{72}{-9}$

⇵

$x\geq -8$

7 0

2 years ago

Read 2 more answers

1/3 + a + 5/4. what is A

USPshnik [31]

Answer:

a = -1.58

Step-by-step explanation:

1/3 +a+5/4 =0

1/3+5/4= -a

4+15/12 = -a

19/12 = -a

1.58= -a

1.58/-1 = -a/-1

-1.58 = a

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B9%7Dx%20-%20%5Cfrac%7B1%7D%7B3%7D%20%3D%20-1" id="TexFormula1" title="\frac{2

egoroff_w [7]

$\large \mathfrak{Solution : }$

let's solve for x :

$\dfrac{2}{9} x - \dfrac{1}{3} = - 1$

$\dfrac{2}{9} x = - 1 + \dfrac{1}{3}$

$\dfrac{2}{9} x = \dfrac{ - 3 + 1}{3}$

$x = \dfrac{ - 2}{3} \times \dfrac{9}{2}$

$x = - 3$

I hope it helped...

7 0

2 years ago

Read 2 more answers

a Car has a 15 gallon gas tank . I f a car gets 32 miles per gallon and travels 384 miles . how much gas will be left in the tan

Komok [63]

Answer:

so you would actually multiply 32 x 15=480 then subtract 480 - 384= it would have 96 miles left. then divide 96/32= 3

so your answer would be 3 gallons left

Step-by-step explanation:

4 0

2 years ago