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RoseWind [281]
3 years ago
12

Laws Of IndiciesCan someone please help me with this?​

Mathematics
2 answers:
nasty-shy [4]3 years ago
8 0

Answer:

See below

Step-by-step explanation:

1) :  {a}^{5}  {b}^{4}  {c}^{3}  \div  {a}^{2}  {b}^{3} c \\  \\  = {a}^{5 - 2}  {b}^{4 - 3}  {c}^{3 - 1}  \\  \\  = {a}^{3}  {b}^{1}  {c}^{2}  \\  \\ = {a}^{3}  {b}  {c}^{2}  \\  \\  \\2)\:  (x^2 y^3)^3\\\\= x^{2\times 3}y^{3\times 3}\\\|= x^{6}y^{9}\\\\\\3)\:5 {a}^{4}   \div ( {a}^{2}  \times 3a) \\  \\  = 5 {a}^{4}   \div (3 {a}^{2 + 1}  ) \\  \\  = 5 {a}^{4}   \div (3 {a}^{3}  ) \\  \\  =   \frac{5}{3}  {a}^{4 - 3}  \\  \\ =   \frac{5}{3}  {a} \\  \\  \\ 4)\: \frac{14 {a}^{5} }{2 {a}^{3} \times 7 {a}^{4}  }  \\  \\  =   \frac{14 {a}^{5} }{2 \times 7 {a}^{3 + 4} }   \\  \\  =   \frac{ \cancel{14} {a}^{5} }{ \cancel{14}{a}^{3 + 4} }    \\  \\  =   \frac{  {a}^{5} }{ {a}^{7} }   \\  \\  =  {a}^{5 - 7}  \\  \\  =  {a}^{ - 2}  \\  \\  =  \frac{1}{{a}^{2} }  \\  \\

Free_Kalibri [48]3 years ago
8 0

Answer:

1.    a^{5} b^{4}c^{3}:a^{2}b^{3}c=a^{3}bc^{2}

2.   (x^{2}y^{3})^{3} =(x^{2} )^{3}(y^{3})^{3}=x^{6}y^{9}

3.    5a^{4}:(a^{2}*3a)=\frac{5a^{4} }{a^{2}*3a } =\frac{5a^{2} }{3a} =\frac{5a}{3}

4.    \frac{14a^{5}} {2a^{3}*7a^{4}}  =\frac{2a}{2a^{3} }=\frac{1}{a^{2} }

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Step-by-step explanation:

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3 years ago
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Alex_Xolod [135]

Answer:

hello :

90 = 15×6

75 =  15× 5

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3 0
3 years ago
Can someone please help me
ss7ja [257]

Answer:

a.) 1/2

b.) 1/8

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d.) 1/2

Step-by-step explanation:

for A it is asking for probability of 1 and is 1/2 of the circle

for B it is asking for  probability of 3 and it is 1/2 of and 1/4 of the circle so 1/8

for C it is asking for probability of the odd numbers and there is tow odd numbers 1 and 3 the probability of 1 is 1/2 and the probability of 3 is 1/8 adding them up will give you 5/8

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6 0
3 years ago
Barack walks 2 kilometers south and then x kilometers east. ​ ​He ends 5 kilometers away from his starting position. ​ ​ Find x
amid [387]

Answer:

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Step-by-step explanation:

-This is a Pythagorean Theorem problem where the distances walked are effectively the base and height of the imaginary right triangle thereof.

#Apply Pythagorean theorem to solve:

b^2+h^2=H^2\\\\2^2+x^2=5^2\\\\x^2=5^2-2^2=21\\\\x=\sqrt{21}\\\\x=4.58\  km

\approx 4.6\ km

Hence, the distance x is 4.6 km

7 0
3 years ago
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spayn [35]

Answer:

Step-by-step explanation:

one way to describe  the prime version  of ABCD is that the sides are all 3 times that of the non- prime version.  So they are when scaled by 3 .. the same.

4 0
3 years ago
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