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RoseWind [281]
3 years ago
12

Laws Of IndiciesCan someone please help me with this?​

Mathematics
2 answers:
nasty-shy [4]3 years ago
8 0

Answer:

See below

Step-by-step explanation:

1) :  {a}^{5}  {b}^{4}  {c}^{3}  \div  {a}^{2}  {b}^{3} c \\  \\  = {a}^{5 - 2}  {b}^{4 - 3}  {c}^{3 - 1}  \\  \\  = {a}^{3}  {b}^{1}  {c}^{2}  \\  \\ = {a}^{3}  {b}  {c}^{2}  \\  \\  \\2)\:  (x^2 y^3)^3\\\\= x^{2\times 3}y^{3\times 3}\\\|= x^{6}y^{9}\\\\\\3)\:5 {a}^{4}   \div ( {a}^{2}  \times 3a) \\  \\  = 5 {a}^{4}   \div (3 {a}^{2 + 1}  ) \\  \\  = 5 {a}^{4}   \div (3 {a}^{3}  ) \\  \\  =   \frac{5}{3}  {a}^{4 - 3}  \\  \\ =   \frac{5}{3}  {a} \\  \\  \\ 4)\: \frac{14 {a}^{5} }{2 {a}^{3} \times 7 {a}^{4}  }  \\  \\  =   \frac{14 {a}^{5} }{2 \times 7 {a}^{3 + 4} }   \\  \\  =   \frac{ \cancel{14} {a}^{5} }{ \cancel{14}{a}^{3 + 4} }    \\  \\  =   \frac{  {a}^{5} }{ {a}^{7} }   \\  \\  =  {a}^{5 - 7}  \\  \\  =  {a}^{ - 2}  \\  \\  =  \frac{1}{{a}^{2} }  \\  \\

Free_Kalibri [48]3 years ago
8 0

Answer:

1.    a^{5} b^{4}c^{3}:a^{2}b^{3}c=a^{3}bc^{2}

2.   (x^{2}y^{3})^{3} =(x^{2} )^{3}(y^{3})^{3}=x^{6}y^{9}

3.    5a^{4}:(a^{2}*3a)=\frac{5a^{4} }{a^{2}*3a } =\frac{5a^{2} }{3a} =\frac{5a}{3}

4.    \frac{14a^{5}} {2a^{3}*7a^{4}}  =\frac{2a}{2a^{3} }=\frac{1}{a^{2} }

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Suppose the scores on an exam are normally distributed with a mean μ = 75 points, and standard deviation σ = 8 points.
Artyom0805 [142]

Answer:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z>\frac{69-75}{8})=P(Z>-0.75)

And we can find this probability on this way:

P(Z>-0.75)=1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problm

Let X the random variable that represent the scores on an exam of a population, and for this case we know the distribution for X is given by:

X \sim N(75,8)  

Where \mu=75 and \sigma=8

We are interested on this probability

P(X>69)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>69)=P(\frac{X-\mu}{\sigma}>\frac{69-\mu}{\sigma})=P(Z>\frac{69-75}{8})=P(Z>-0.75)

And we can find this probability on this way:

P(Z>-0.75)=1-P(Z

4 0
3 years ago
3. Determine which ordered pair is not a solution of y = –5x – 4.
erastovalidia [21]

Answer:

A

Step-by-step explanation:

Let's try choice A.

y = -5x-4

(10, -52)

-52 = -5(10)-4

-52 = -50-4

-52= -54

-52 is not equal to -54, so A is the answer.

5 0
3 years ago
(a^(?))/(a^(10))= a^(4) help me
UNO [17]

Answer:

a^? = 14

Step-by-step explanation:

a^? / a^10 = a^4

is also the same as

a^? - a^10 = a^4 ( due to laws of indices)

a^? = a^4 + a^10

a^? = a^14

the a's striking each other resulting in

? = 14

7 0
3 years ago
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Colt1911 [192]

Answer:

7 flower bunches

Step-by-step explanation:

One flower bunch requires 12 roses since 48/4 is 12

then to find out how many flower bunches can be made by 84 roses you would have to divide 84 by 12 which gives you 7.

7 0
3 years ago
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sergejj [24]

Answer:

5%

Step-by-step explanation:

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