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allsm [11]
3 years ago
10

What’s the correct answer or this?

Mathematics
2 answers:
zalisa [80]3 years ago
8 0

Answer:

B

Step-by-step explanation:

Sin ∅ =opposite/HYPOTENUSE

Sin 55 =opposite/35

0.82×35=opposite

Opposite=28.7 feet

Harman [31]3 years ago
6 0

Answer:

Height = 35 x sin(55deg) = ~28.7 feet

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Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
At the beach, Nardia collected triple the number of seashells that Pierre did. Together, they collected 52 seashells. Which equa
Whitepunk [10]

Answer:

p=number of seashells pierre collected

p+3p=52

4p=52

p=13

13 seashells

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3 years ago
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Add those together is 7/10
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Given deductions for this week: federal tax $61.34, FICA $52.05, and state $7.92 what is the annual federal tax deduction?
stealth61 [152]

Given the weekly deductions raised, the annual Federal Tax deduction is $ 3,189.68.

Given that the deductions for the week were: Federal Tax $ 61.34, FICA $ 52.05, and State $ 7.92; To determine what is the annual Federal Tax deduction, the following calculation must be performed:

The weekly deduction must be multiplied by the number of weeks that a year has, to obtain the final amount of taxes.

  • $ 61.34 x 52 = X
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Therefore, the annual Federal Tax deduction is $ 3,189.68.

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Answer:

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Step-by-step explanation:

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