Answer:
Part A: (1/2)m
Part B: (1/3rd)b and 3mx
Step-by-step explanation:
Price of each baseball is=$m
Price of other equipment are=$b collectively
Total amount He spent on purchasing equipment is =(m+b)$
Part A:
in part A the amount on purchasing other equipment than baseball is getting doubled i.e. $2b <u> then value of m will be (1/2)half of the total amount spent on purchasing baseball i.e. (1/2)m</u>
Part B:
in part B the amount spent on purchasing baseball is getting tripled i.e. <u>3m</u>, then value of b(amount of purchasing other equipment) is<u> (1/3rd) of total</u> <u>amount spent on purchasing other equipment</u> and value of mx will be<u> 3mx</u>
F(x) > g(x)
2^x + 3 > 50x + 5
for x = 3 , f(3) > g(3)
11 > 155 (false)
for x = 10 , f(10) > g(10)
1027 > 505 (true)
for x = 9 , f(9) > g(9)
515 > 455 (true)
for x = 8 , f(8) > g(8)
259 > 405 (false)
the smallest,positive integer value of x is 9 since the value of 9 is the last number to exceeds g(x)
![\bf tan(x^o)=1.11\impliedby \textit{taking }tan^{-1}\textit{ to both sides} \\\\\\ tan^{-1}[tan(x^o)]=tan^{-1}(1.11)\implies \measuredangle x=tan^{-1}(1.11)](https://tex.z-dn.net/?f=%5Cbf%20tan%28x%5Eo%29%3D1.11%5Cimpliedby%20%5Ctextit%7Btaking%20%7Dtan%5E%7B-1%7D%5Ctextit%7B%20to%20both%20sides%7D%0A%5C%5C%5C%5C%5C%5C%0Atan%5E%7B-1%7D%5Btan%28x%5Eo%29%5D%3Dtan%5E%7B-1%7D%281.11%29%5Cimplies%20%5Cmeasuredangle%20x%3Dtan%5E%7B-1%7D%281.11%29)
plug that in your calculator, make sure the calculator is in Degree mode
2x - 5x + 4 = 0
- 3x = - 4
x = 4/3
Answer:
x=y-6
Step-by-step explanation:
First, flip the equation.
x+6=y
Finally, add -6 to both sides.
x+6+−6=y+−6
x=y−6
