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mamaluj [8]
3 years ago
13

Rationalize the denominator of (click photo)

Mathematics
1 answer:
Ede4ka [16]3 years ago
6 0
\frac{\sqrt{-49}}{(7-2i)-(4+9i)}=\\
\frac{\sqrt{-1*7*7}}{3-11i}=\\
\frac{7i}{3-11i}*\frac{3+11i}{3+11i}=\\
\frac{(7i)*(3+11i)}{3^2-(11i)^2}=\\
\frac{21i+77i^2}{9+121}=\\
\frac{21i-77}{130}=\\
\frac{-77+21i}{130}

so it is the last option
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What is the total number of servings the modified recipe will make?
Digiron [165]

9514 1404 393

Answer:

  B.  4

Step-by-step explanation:

Equating exponents, we have ...

  2x +7 = 15

  2x = 8 . . . . . subtract 7

  x = 4 . . . . . . divide by 2

The equation is true when the value of x is 4.

5 0
2 years ago
Read 2 more answers
6.) -2x + y = -1<br><br> X Y<br> -4<br> -3<br> -2<br> 1<br> 0
MrRa [10]

Answer:

Step-by-step explanation:

i ASSUME THE QUESTION IS TO DETERMINE Y?  

Rearrange the equation  to y = 2x - 1 and solve for each value of x

<u>X</u>  <u>Y</u>

-4  -9

-3  -7

-2  -5

1   1

0  -1

7 0
2 years ago
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

4 0
3 years ago
Use substitution to solve the following system of linear equations and fill in the following blanks:
marissa [1.9K]

Answer:

x=-4

y=3

z=-5

Step-by-step explanation:

<u>Given:</u>

x+y+z=-6

x-6y-7z=-29

-7y-5z=4

<u>Solve for </u>x<u> in the 1st equation:</u>

x+y+z=-6

x+y=-z-6

x=-y-z-6

<u>Substitute the value of </u>x<u> into the 2nd equation and solve for </u>z<u>:</u>

x-6y-7z=-29

(-y-z-6)-6y-7=-29

-7y-z-13=-29

-7y-z=-16

-z=-16+7y

z=16-7y

<u>Substitute the value of </u>z<u> into the 3rd equation and solve for </u>y<u>:</u>

-7y-5z=4

-7y-5(16-7y)=4

-7y-80+35y=4

28y-80=4

28y=84

y=3

<u>Plug </u>y=3<u> into the solved expression for </u>z<u> and evaluate to solve for </u>z<u>:</u>

z=16-7(3)

z=16-21

z=-5

<u>Plug </u>z=-5<u> into the solved expression for </u>x<u> and evaluate to solve for </u>x<u>:</u>

x=-(3)-(-5)-6

x=-3+5-6

x=2-6

x=-4

Therefore:

x=-4

y=3

z=-5

6 0
3 years ago
PLEASE HELP
Andrej [43]

Answer: -3 and 0

Step-by-step explanation: f(x) = g(x) where they intersect. Two lines intersect when they have the same x and y values.

5 0
3 years ago
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