Answer:
x = +-sqrt(3) and they are the actual solutions
Step-by-step explanation:
x^2/ (2x-6) = 9/(6x-18)
get a common denominator of 6x-18
x^2/ (2x-6) * 3/3 = 9/(6x-18)
3x^2/ (6x-18) = 9/(6x-18)
since the denominators are the same, the numerators must be the same
3x^2 = 9
divide by 3 on each side
x^2 = 3
take the square root of each side
sqrt(x^2) = +-sqrt(3)
x = +-sqrt(3)
Let the boat speed in still water be b.
Let the current speed be c.
The speed going upstream is 20/4 = 5 mph.
The speed going downstream is 32/4 = 8 mph.
b - c = 5 ........(1)
b + c = 8 .......(2)
Adding equations (1) and (2) we get:
2b = 13
b = 13/2 = 6.5
Plugging in the value for b into equation (1) we find c = 1.5.
The boat speed in still water is 6.5 mph and the current speed is 1.5 mph.
Hey!
So before trying to figure out the equation of the line, lets change -3y+4x = 9 into slope-intercept form:
-3y + 4x = 9
-3y = -4x + 9
y = (4/3)x - 3
Now that you have the equation in slope-intercept form we can find the equation of the line parallel to this. One thing that we are given from this equation is the slope of the line, the slope for two parallel lines are the same. So we know that the slope of the line is 4/3. We are also given another point on the line and we can plug this point in for y and x to find the y-intercept or b:
6 = (4/3)(-12) + b
6 = -16 + b
22 = b
Now that we know b, we have both the y-intercept and the slope so our equation would be:
y = (4/3)x + 22
Use the slope formula (y2-y1)/(x2-x1)
(0+9)/(4+7)=9/11
Since q is parallel to r the slope will be the same. 9/11 is the slope of line r
