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Rom4ik [11]
3 years ago
12

From a fraction to a decimal 19/20

Mathematics
1 answer:
REY [17]3 years ago
5 0
It would be 0.95 you judt divide the top jumberto thebottom one
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If (-1, y) lies on the graph of y=2^2x then y=
zubka84 [21]

Answer:

y is 1/4 when x is -1 if I did interpret your equation right. Please see that I did.

I believe the equation to be y=2^{2x}.  If you meant y=2^2x, please let me know.

Thanks kindly.

Step-by-step explanation:

If (-1,y) lies on the graph of y=2^{2x}, then by substitution we have:

y=2^{2\cdot -1}.  

We just need to simplify to determine y:

y=2^{2 \cdot -1}  

Multiply the 2 and -1:

y=2^{-2}

Use reciprocal rule for exponents to get rid of the negative:

y=\frac{1}{2^2}

2^2 just means 2(2):

y=\frac{1}{2(2)}

y=\frac{1}{4}.

8 0
3 years ago
Select all that apply If 2x^2-6x=0, then​
babymother [125]

Answer:

then 2x = 0 and x - 3 = 0

Step-by-step explanation:

4 0
3 years ago
Which of the relations given by the following sets of ordered pairs is not a function?
-Dominant- [34]

Answer:

Hi, there your answer will be C.

Step-by-step explanation:

The reason why is because X(Input) can not be repeated the same

for example the coordiante( 1,3) and (1,4). See there are two ones which make them not function

Also, if you're having trouble with Functions and nonfunctions

REMEMBER THS

Function: X and y has to be separarte  and can't have the same X

NON-FUNCTION- WHEN X REPEATS ITSELF

Hope this helps :)

7 0
3 years ago
What is the equation of a circle whose center is (2,0) and has a radius= 9?
Flauer [41]
The equation of a circle is: (x - h)² + (y - k)² = radius² where (h, k) is the center. Now just plug in your given information and simplify.

(x - 2)² + (y - 0)² = 9²

Your equation is:
(x - 2)² + y² = 81
6 0
3 years ago
Read 2 more answers
Consider the functions. F(x)=(x+1)2-4 and g(x)=-4|x+1| which statement compares the range of the functions?
Andreyy89

Answer:

<h2>        The fourth</h2>

Step-by-step explanation:

Vertex of f is (-1, -4) so its range is limited to y≥-4

|x+1| is always ≥0 therefore -|x+1| is always ≤0 {4 is insignificant to this - slope doesn't mean in range} so its range is limited to y≤0

3 0
3 years ago
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