Question

Question 12.12. In 2010, the population of a city was 65,903. It was expected to grow at a rate of 0.7% each year.

Answer 1

$y=Ce^{kx}$

k=0.7%=0.007

$65903=Ce^{.007(0)} \\ 65903=Ce^0 \\ 65903=C(1) \\ C = 65903$

$y=65903e^{0.007(2027-2010)}\\y=65903e^0.229 \\ y = 74231.157$

The best answer is 74,200