Step-by-step explanation:
Frequency of a mass-spring system is:
f = √(k/m) / (2π)
Given f = 2/π Hz and m = 20 kg:
2/π Hz = √(k / 20 kg) / (2π)
4 Hz = √(k / 20 kg)
16 s⁻² = k / 20 kg
k = 320 kg/s²
k = 320 N/m
If the 20 kg mass is replaced with an 80 kg mass, the frequency is:
f = √(320 kg/s² / 80 kg) / (2π)
f = √(4 s⁻²) / (2π)
f = 2 Hz / (2π)
f = 1/π Hz
36/40 = 90%
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work
36/40= 0.9
0.9x100 =90
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The order is >,<,> hope this helps
Answer: 32,00,000
Step-by-step explanation:
We can use the formula
16,00,000 x 0.5 x 2 = 16,00,000
Total no. of students using Khan Academy after 2 years will be:
1600000 + 1600000 = 32,00,000
Answer:
Decimal comparison
Step-by-step explanation:
your question is incomplete btw
