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sergij07 [2.7K]
4 years ago
5

Graph the function f(x)=32x−4. Use the line tool and select two points to graph.

Mathematics
2 answers:
erma4kov [3.2K]4 years ago
8 0

Answer with Step-by-step explanation:

We are given that a function

f(x)=32x-4

We have to graph the given function by using line tool.

To find the y-intercept:

Substitute x=0 then we get

f(0)=32(0)-4=-4

The function f(x) intersect the y-axis at point (0,-4).

To find the x-intercept :

Substitute y=0

Then , we get

0=32x-4

32x=4

x=\frac{4}{32}=0.125

Therefore, the function intersect the x- axis at point (0.125,0).

Now, mark the points on the graph and then meet these points.

muminat4 years ago
4 0

Answer:

I believe the points (0,-4) and (1,28) work. You can also use (0.125,0) if you can.

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quadrilateral A'B'C'D' is the image of quadrilateral ABCD after being translated 6 units up and 7 units left. Quadrilateral A pr
Firlakuza [10]

Answer:

B(x,y) = (-10,-1)

Step-by-step explanation:

Given

B' = (-3,5)

Required

Determine B

When a point is translated up, the result is:

y'->y + h

Where h is the unit translated

y' is the new point and y is the previous;

So, we have

5 = y + 6

y = 5 - 6

y = -1

When a point is translated left, the result is:

x'->x + h

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x' is the new point and x is the previous;

So, we have

-3 = x + 7

x = -3 - 7

x = -10

Hence, the coordinates of B is

B(x,y) = (-10,-1)

8 0
3 years ago
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What is the answer is it a,b,c or d ?
Nezavi [6.7K]

Answer:

A

Step-by-step explanation:

Grab a ruler and a compass draw a circle and think about it

5 0
4 years ago
Please need help on this one
____ [38]

Answer:

x = 0.

Step-by-step explanation:

5x - 15 = 5(-4x - 3)

5x - 15 = -20x - 15

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4 years ago
A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum,  we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = \frac{x^{2} }{16}

For the equilateral triangle, the length of the side =  \frac{23 - x}{3}

Area = \frac{\sqrt{3} }{4}  a^{2}  = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}

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\frac{dA}{dx}  = \frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x)\\

\frac{d^{2}A }{dx^{2} }  = \frac{1}{8}  + \frac{\sqrt{3} }{18}  > 0, therefore it is minimum

\frac{dA}{dx}  = 0 \\\\

\frac{x}{8}  -  \frac{\sqrt{3} }{18} (23 - x) = 0\\

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3 years ago
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PLEASE HELP NEED ANSWER ASAP 15 POINTS WILL MARK BRAINLIEST!!
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Answer: slope = -3 and (-2,6) is a point on the line

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Step-by-step explanation:


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