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sergij07 [2.7K]
3 years ago
5

Graph the function f(x)=32x−4. Use the line tool and select two points to graph.

Mathematics
2 answers:
erma4kov [3.2K]3 years ago
8 0

Answer with Step-by-step explanation:

We are given that a function

f(x)=32x-4

We have to graph the given function by using line tool.

To find the y-intercept:

Substitute x=0 then we get

f(0)=32(0)-4=-4

The function f(x) intersect the y-axis at point (0,-4).

To find the x-intercept :

Substitute y=0

Then , we get

0=32x-4

32x=4

x=\frac{4}{32}=0.125

Therefore, the function intersect the x- axis at point (0.125,0).

Now, mark the points on the graph and then meet these points.

muminat3 years ago
4 0

Answer:

I believe the points (0,-4) and (1,28) work. You can also use (0.125,0) if you can.

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kow [346]

Let's let

<u>x = the number of chef salads, x>=0</u>

<u>y = the number of Caesar salads, y>=0</u>

The constrains are:

40 <= x <= 60

35 <= y <= 50

x + y <= 100

The objective function here is F(x, y) = 0.75x + 1.20y

The corner points are (40, 35),  (60, 35), (60, 40), (50, 50) and (40, 50).

F (40, 35) = 0.75*40 + 1.20*35 = $72

F (60, 35) = 0.70*60 + 1.20*35 = $84

F (60, 40) = 0.75*60 + 1.20*40 = $93

F (50, 50) = 0.75*50 + 1.20*50 = $97.50

F (40, 50) = 0.75*40 + 1.20*50 = $90

Thus, we conclude to maximize the profit 50 Chef and 50 Caesar salads should be prepared.

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3 years ago
Sam has sewn three square tablecloths of different sizes. He determines the length of the diagonal of each square tablecloth.
Reika [66]

Answer:

Step-by-step explanation:

the square root of 12 is 3.4 so the answer is 3.4

5 0
2 years ago
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Find the value of 15 - 8 ÷ 2.
Mamont248 [21]

8÷2= 4

15-4= 11

  1. First you divide 8 by 2.
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TAKE 50 POINTS!!!!!!please Someone HELP.JUST look the picture. ​
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Step-by-step explanation:

M=\left[\begin{array}{ccc}1&-1/f_2\\0&1\end{array}\right] \left[\begin{array}{ccc}1&0\\d&0\end{array}\right] \left[\begin{array}{ccc}1&-1/f_1\\0&1\end{array}\right]\\=\left[\begin{array}{ccc}1&-1/f_2\\0&1\end{array}\right]\left[\begin{array}{ccc}1&-1/f_1\\d&-d/f_1\end{array}\right]\\=\left[\begin{array}{ccc}1-d/f_2&-1/f_1+d/f_1f_2\\d&-d/f_1\end{array}\right]\\\\|M|=[-d/f_1+d^2/f_1f_2]-[-d/f_1+d^2/f_1f_2]=0\\\\-1/f=M_{12}=-1/f_1+d/f_1f_2\\1/f=M_{12}=+1/f_1-d/f_1f_2\\

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