If Michael has $2 and he spends $1, how much money does he have left? We can figure this out by subtracting $1 from $2. This is obviously equal to $1.
We can use the same idea for this problem. George starts with $23 and spends at least $14. After this, George has 23 - 14 = $9 dollars left. So, George can spend $9 at the max.
We can translate this into math words by saying George can spend less than 9 on glue, so p < 9. So, a. is the correct answer.
Answer:
A^(2) + B^(2) = C^(2)?????????????
Step-by-step explanation:
that's an isosceles triangle, not a right-angle triangle
Using the law of cosin
cos(angle) = adjacent leg / hypotenuse
We fill in what we know and solve for x:
cos(30) = x / 10
x = cos(30) * 10
x = 5 SQRT(3)
4d = 24 would be the right equation. To double check you would divide both sides by 4 (the number of legs) to find the amount of dogs.