Since LM = AM, point M must be on the perpendicular bisector of AL. Since AM = BM, BL must be perpendicular to AL. This makes ∆ALC a right triangle with hypotenuse AC twice the length of side AL. Hence ∠LAC = ∠LAB = 60°, and AL is angle bisector, median, and altitude.
ΔABC is isosceles with ∠A = 120°, and ∠B = ∠C = 30°.
Answer:
25
Step-by-step explanation:
Let n be the first integer.
Then the second integer will be (n + 1).
And the third will be (n + 2).
The sum is 78. Therefore:
Solve for n. Combine like terms:
So:
Therefore:
Therefore, the first integer is 25.
So our sequene is 25, 26, and 27.
The integer closest to zero will thus be 25.
Answer:
the first problem is - 85 and you continue from there
We have the price of a senior ticket is $4 and the price of a child ticket is $7
Step-by-step explanation:
We can form two equations, let the price of a senior ticket be s and the price of a child ticket be c.
We have from day 1:
A: 3s + 9c = 75
And from day 2:
B: 8s + 5c = 67
Now we can rewrite A as:
A: 24s + 72c = 600
And can rewrite B as:
B: 24s + 15c = 201
Now A-B can be written as:
A-B: 57c = 399
So c = 7
Now substituting this back into A we get:
A: 3s + 63 = 75
A: 3s = 12
So s = 4
We have the price of a senior ticket is $4 and the price of a child ticket is $7
